Answer:
look above
Step-by-step explanation:
hope it helps
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
Its the y=3x2one pretty sure
Answer:
x > 1/9
Step-by-step explanation:
Given that:
3x-1>-6x
Adding 6x + 1 on both sides we get
3x-1 + 6x + 1>-6x + 6x +1
3x + 6x > 1
Adding both variables
9x > 1
Dividing both sides b 9 we get
9x/9 > 1/9
x > 1/9
I hope it will help you!
