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fenix001 [56]
4 years ago
10

-

\sqrt{5 } - 3 \sqrt{5} " alt=" - \sqrt{5 } - 3 \sqrt{5} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
xxTIMURxx [149]4 years ago
3 0

Step-by-step explanation:

-\sqrt5-3\sqrt5=-1\sqrt5-3\sqrt5=(-1-3)\sqrt5=-4\sqrt5

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Mandy divided the sum of 12 and
Aleksandr [31]

Answer:

35

Step-by-step explanation:

I hope this helps you.

12+24=38

38÷6=31

31+4=35

4 0
3 years ago
Giving brainlist to whoever answers
just olya [345]

Answer:

False

Step-by-step explanation:

V=bhw\\V=7.5*13*2\\V=195

6 0
3 years ago
(2x² - 5) - (3x² + 4).
Goshia [24]

(2x² - 5) - (3x² + 4).

Pretend that there is a -1 in front of :(3x² + 4).

(2x^2-5)-1(3x^2+4)

2x^2-5-3x^-4

2x^2-3x^2-5-4

=-x^2-9

Answer: -x^2-9

3 0
4 years ago
The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
4 years ago
If y = -5 when x = 2, find y when x = 8.
nasty-shy [4]

Answer:

Y= -20

Step-by-step explanation:

if y=-5 when x=2 find y when x=8

8 /2 = 4

=> x = 2 * 4 => x = 8 Answer

y = -5 * 4 =>

y= -20

4 0
2 years ago
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