Answer:
I think it would be
t(15,200)¹'⁰⁴
I used an apostrophe up there, but it's supposed to be a dot, so to the power of 1.04
Answer:

Step-by-step explanation:
The complete question in the attached figure
we know that
The surface area of a cube is equal to the area of its 6 squares faces
so
The area of one square face is equal to

where
b is the length side of the square
we have

substitute
---> area of one square face
Find the surface area of three cubes
Multiply the area of one square face by 6 (one cube has 6 faces) and then multiply the result by 3 (3 cubes)
so
![SA=3[6(1)]=18\ ft^2](https://tex.z-dn.net/?f=SA%3D3%5B6%281%29%5D%3D18%5C%20ft%5E2)
Cramer's rule works as follows:
x+3y=16
3x+y=8
Then
x=Dx/D
y=Dy/D
where Dx,Dy,D are 2x2 matrices formed from of coefficients and right hand side.
D=
1 3
3 1
=1-9=-8
Dx=matrix D with first column replaced by the vector [16,8]=
16,3
8 1
=16-24
=-8
Dy=matrix D with second column replaced by the vector [16,8]=
1 16
3 8
=8-48
=-40
Therefore
x=-8/-8=1
y=--40/-8=5
Check:
x+3y=1+3(5)=16
3x+y=3(1)+5=8 ok.
The range will be all ur y values...just as the domain is all the x values
so ur range is {5,6 }...notice that even though they repeat, u only have to list them once
Answer:
Length:28 cm
Width: 13 cm
Step-by-step explanation:
Let
x ---> the length of a rectangle picture frame
y ---> the width of a rectangle picture frame
we know that
The area of a rectangle picture frame is equal to

we have

so
----> equation A
The length of a rectangle picture frame is 2 centimeters more than twice it’s width
so
---> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
The solution is the point (28,13)
see the attached figure
therefore
Length:28 cm
Width: 13 cm