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3 years ago

21x-5=7+17x Write it down step by step please

Mathematics

2 answers:

Nat2105 [25]3 years ago

4 0

Answer: x=3

Step-by-step explanation: Step 1: Simplify both sides of the equation.

21x−5=7+17x

21x+−5=7+17x

21x−5=17x+7

Step 2: Subtract 17x from both sides.

21x−5−17x=17x+7−17x

4x−5=7

Step 3: Add 5 to both sides.

4x−5+5=7+5

4x=12

Step 4: Divide both sides by 4.

$\frac{4x}{4}$ = $\frac{12}{4}$

So Final Answer: x=3

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

natta225 [31]3 years ago

4 0

Answer:

x=3

Step-by-step explanation:

21x-5=7+17x

21x-17x=7+5

4x= 12

x=12÷4

x=3

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Find a polynomial $f(x)$ of degree $5$ such that both of these properties hold: $\bullet$ $f(x)$ is divisible by $x^3$. $\bullet

frosja888 [35]

There seems to be one character missing. But I gather that f(x) needs to satisfy

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I'll also assume f(x) is monic, meaning the coefficient of the leading term is 1, or

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Since $x^3$ divides $f(x)$ , and

$f(x) = x^3 p(x)$

where $p(x)$ is degree-2, and we can write it as

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Now, we have

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so if $(x - 1)^3$ divides $f(x)^2$ , then $p(x)$ is degree-2, so $p(x)^2$ is degree-4, and we can write

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Expanding the left side gives

$p(x)^2 = x^4 + 2ax^3 + (a^2+2b)x^2 + 2abx + b^2$

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$\dfrac{p(x)^2}{(x-1)^3} = \underbrace{x + 2a + 3}_{q(x)} + \dfrac{(a^2+6a+2b+6)x^2 + (2ab-6a-8)x +2a+b^2+3}{(x-1)^3}$

If the remainder is supposed to be zero, then

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Adding these equations together and grouping terms, we get

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$p(x) = x^2 - 2x + 1 \\\\ \implies f(x) = x^3 (x^2 - 2x + 1) = \boxed{x^5-2x^4+x^3}$

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3 years ago

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IRINA_888 [86]

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4:20 could turn into 2:10 by dividing both numbers by 2.

And 8:40 could be divided by 4 to get 2:10.

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tamaranim1 [39]

Answer:

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Step-by-step explanation:

i hope this helps :)

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Nesterboy [21]

Answer:

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Step-by-step explanation:

When x = 0

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y + 3 = √8 or -y - 3 = √8

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The mid point between these two is the average

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