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Maru [420]
3 years ago
5

The burning times of scented candles, in minutes, are normally distributed with a mean of 249 and a standard deviation of 20. Fi

nd the number of minutes a scented candle burns if it burns for a shorter time than 60% of all scented candles.
Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0

Answer:

The candle burns for 244 minutes.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 249, \sigma = 20

Find the number of minutes a scented candle burns if it burns for a shorter time than 60% of all scented candles.

This is the 100-60 = 40th percentile, which is X when Z has a pvalue of 0.4. So X when Z = -0.253.

Z = \frac{X - \mu}{\sigma}

-0.253 = \frac{X - 249}{20}

X - 249 = -0.253*20

X = 244

The candle burns for 244 minutes.

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It is also given that, Call center remain open for 10 hours 5 days a week.

Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week  ,Part time agents work 20 hours a week but are only on calls 17 hours per week .

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