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3 years ago

How would you write 14 divided by 20 as a decimal?

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

8 0

Answer:

0.7

Step-by-step explanation:

14/20 = 70/100 (to make the denominator 100, you would multiply by 5)

70/100 = 0.7

sdas [7]3 years ago

5 0

Answer:

14 divided by 20 is equals to 0.7!

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If 9<15mx-8<279<15mx−8<279, is less than, 15, m, x, minus, 8, is less than, 27, where mmm is a positive constant, wh

rewona [7]

Answer:

The range of $\frac{8}{3}-5mx$ is (-9,-3).

Step-by-step explanation:

The given compound inequality is

$9$

We need to find the range of values of $\frac{8}{3}-5mx$ .

Let $y=\frac{8}{3}-5mx$

Divide each side of the given compound inequality by 3.

$\frac{9}{3}$

$3$

Multiply each side by -1.

If we multiply an inequality by a negative number, then the sign of inequality is changed.

$3(-1)>(5mx-\frac{8}{3})(-1)>9(-1)$

$-3>-5mx+\frac{8}{3}>-9$

$-3>\frac{8}{3}-5mx>-9$

$-3>y>-9$

Therefore the range of $\frac{8}{3}-5mx$ is (-9,-3).

5 0

4 years ago

"(b) use part (a) to find a power series for f(x) = 1 (4 + x)3 ."

Firdavs [7]

Assuming

$f(x)=\dfrac1{(4+x)^3}$

Recall that for $|x|$ ,

$\displaystyle\sum_{n\ge0}x^n=\frac1{1-x}$

Denote the above by $s(x)$ . Then

$s'(x)=\displaystyle\sum_{n\ge1}nx^{n-1}=\frac1{(1-x)^2}$
$s''(x)=\displaystyle\sum_{n\ge2}n(n-1)x^{n-2}=\frac2{(1-x)^3}$

Now,

$\dfrac1{(4+x)^3}=\dfrac1{4^3}\dfrac1{\left(1-\left(-\frac x4\right)\right)^3}=\dfrac1{2^7}\dfrac2{\left(1-\left(-\frac x4\right)\right)^3}$

which means we have

$f(x)=\dfrac1{2^7}s''(x)=\dfrac1{128}\displaystyle\sum_{n\ge2}n(n-1)\left(-\frac x4\right)^{n-2}$

which is valid for $\left|-\dfrac x4\right|$ , or $|x|$ .

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3 years ago

-b+10=5b-8 what does b equal

maksim [4K]

Answer: b = 3

Step-by-step explanation:

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3 years ago

Read 2 more answers

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klio [65]

Answer:

3/5

Step-by-step explanation:

2/3 and 3/5 have a common denominator of 15 so multiply 2/3 by 5 and 3/5 by 3 and you will get 10/15 from 2/3 and 3/5 is 9/15 so it is less then 2/3

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3 years ago

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Neko [114]

See https://web2.0calc.com/questions/i-m-confused_17.

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