Answer:
x is 11
Step-by-step explanation:
We know the slope (3/4) and a point (3,-4), so we can use point-slope form (y-y1=m(x-x1)
Substitute the numbers into the equation
y--4=3/4(x-3)
simplify
y+4=3/4(x-3)
do the distributive property
y+4=3/4x-9/4
subtract 4 from both sides
y=3/4x-25/4
this is the equation of the line.
Since it says that (x,2) is a point in the equation, we can substitute it into the equation
2=3/4x-25/4
add 25/4 to both sides
33/4=3/4x
multiply by 4/3
11=x
we can double check by plugging (11,2) into the equation of the line.
2=3/4(11)-25/4
2=33/4-25/4
2=2
it works! :)
Hope this helps!
Answer:
(A)
Length of DE = √17
EF = √18
DF = √17
(B) Slope of DE = 4
EF = 1
DF = 1/4
(C) Isosceles triangle.
Step-by-step explanation:
See attached image.
Answer:

Step-by-step explanation:
The expression to transform is:
![(\sqrt[6]{x^5})^7](https://tex.z-dn.net/?f=%28%5Csqrt%5B6%5D%7Bx%5E5%7D%29%5E7)
Let's work first on the inside of the parenthesis.
Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:
![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Therefore ![\sqrt[6]{a} = a^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now let's replace
with
which is the algebraic form we are given inside the 6th root:
![\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Bx%5E5%7D%20%3D%20%28x%5E5%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now use the property that tells us how to proceed when we have "exponent of an exponent":

Therefore we get: 
Finally remember that this expression was raised to the power 7, therefore:
[/tex]
An use again the property for the exponent of a exponent:
Answer:
B is the answer because yes