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4 years ago

Central City is creating Park B, which will be a pentagon shape and geometrically similar to Park A.

Mathematics

1 answer:

AnnyKZ [126]4 years ago

7 0

Answer:

3rd answer is true

Step-by-step explanation:

The corresponding angles of both parks are congruent; the ratio of the perimeters of Park A to Park B is 2:5.

As you speak of angles being the same.

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Svetllana [295]

Answer:

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Step-by-step explanation:

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3 years ago

What is the equation of the line that is parallel to 3x-5y=7 and passes through the point (-10,8)

Karo-lina-s [1.5K]

Answer: y= 3/5 + 18

Step-by-step explanation: Bruh i legit learned this a hour ago at my tuition, ok so basically simply to slope intercept from ye? so it would be y=-3/5x+7

and then you would use the distance formula and ye distance formula is square root of x sub 2 - x sub 1 squared+ y sub 2 - y sub 1 squared

4 0

4 years ago

2/3y - 2/5 = 5 and please show work Algebra

Travka [436]

2/3y-2/5=5

We move all terms to the left:

2/3y-2/5-(5)=0

Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R

determiningTheFunctionDomain

2/3y-5-2/5=0

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3 0

3 years ago

Read 2 more answers

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Each wheel on Nina's car has has a diameter of 18 inches.Which expression could be used to find the circumference of the wheel?

serg [7]

Answer:

56.548667764616276

Step-by-step explanation:

Multiply the diameter by pi.

C= 18 x 3.14159265

Hope this helps!

7 0

3 years ago