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lilavasa [31]
3 years ago
13

Referring to the figure, find the value of x

Mathematics
2 answers:
Lorico [155]3 years ago
8 0

Answer:

Step-by-step explanation:

By the triangle angle-sum theorem, all the angles of a triangle have to add up to equal 180°.  Thus,

72° + 5x° + x° = 180° and

72° + 6x° = 180° and

6x° = 108° so

x = 18°

asambeis [7]3 years ago
3 0
A scale of 1:50 000 means that every centimetre on the map is equal to 50 000 centimetres (500 metres) in reality.

The distance between two towns on that map is 6cm, therefore in reality there’s 6 * 50 000 = 300 000 centimetres, which is equal to 3 000 metres, which is equal to 3 kilometres.
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Factorize: 3x²+54x + 243​
Andrew [12]

Answer:

3(x + 9)(x + 9)

Step-by-step explanation:

  1. 3x^2 + 54x + 243
  2. 3(x^2 + 18x + 81)

a + b = 18

a + b = 81

a= = 9, b = 9

3. 3(x + 9)(x + 9)

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2 years ago
Suppose that the relation S is defined as follows.S = ( -6,0), (5,-3), (-6,-1), (-8,5)Give the domain and range of S. Write your
Angelina_Jolie [31]

The domain of a relation is all the x - values the relation can take, so:

domain = {-8, -6, 5}

The range, in addition, is all the y - values the relation can take, so:

range = {-3, -1, 0, 5}

3 0
1 year ago
______% of 200 miles is 150 miles.
Genrish500 [490]

Answer:

75%

Step-by-step explanation:

150/200 × 100 =75

6 0
3 years ago
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How wide and how long is the actual swimming pool
Ber [7]

Answer:

ig 50 meters long by 25 meters wide

Step-by-step explanation:

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4 0
3 years ago
Log_c(A)=2<br> log_c(B)=5, <br> solve log_c(A^5B^3)
vlabodo [156]

We know that \log_a(bc)=\log_a(b)+\log_a(c).

Using this rule,

\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3).

We also know that \log_c(a^b)=b\log_c(a).

Using this rule,

\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)

Now we know that \log_c(A)=2,\log_c(B)=5 so,

5\cdot2+3\cdot5=10+15=\boxed{25}.

Hope this helps :)

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3 years ago
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