Question

BRAINLIEST ASAP! PLEASE HELP ME :)

Answer 1

The answer is √91,10

Answer 2

Answer:  Choice B

$\frac{\sqrt{91}}{10}$

sqrt(91)/10

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Work Shown:

Angle $\theta$ is in Q1 since $0 \le \theta \le 90$

$\sin \theta = \frac{3}{10}$

$\sin^2 \theta = \left(\frac{3}{10}\right)^2 = \frac{9}{100}$

$\cos^2\theta = 1-\sin^2\theta$

$\cos^2\theta = 1-\frac{9}{100}$

$\cos^2\theta = \frac{100}{100} - \frac{9}{100}$

$\cos^2\theta = \frac{91}{100}$

$\cos\theta = \sqrt{\frac{91}{100}}$ .... cosine is positive in Q1

$\cos\theta = \frac{\sqrt{91}}{\sqrt{100}}$

$\cos\theta = \frac{\sqrt{91}}{10}$