Ask question

Ask question

All categories

3 years ago

7

What type of wave allows you to hear sounds?

2 answers:

DIA [1.3K]3 years ago

8 0

Electromagnetic transverse waves

Galina-37 [17]3 years ago

6 0

Electromagnetic transverse waves

You might be interested in

A FORCE OF 5N ACTS ON A 15 KG BODY INITIALLY AT REST THE WORK DONE BY THE FORCE DURING THE FIRST SECOND OF THE MOTION OF THE BOD

aleksandr82 [10.1K]

There answer is C 5/6

3 0

3 years ago

A charged object is suspended motionless in the air by the gravitational force pulling it down and an electric force pushing it

Savatey [412]

The charge of the object must be $1.11 \times e^{-5} \text { coulomb }$

Answer: Option C

<u>Explanation:</u>

Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.

Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.

$Electric field, E=\frac{\text { Force }(F)}{q}$

Here, given E = 4500 N/C and F = 0.05 N.

We need to find charge of the object (q)

By substituting the given values, we get

$q=\frac{F}{E}=\frac{0.05 N}{4500 \mathrm{N} / \mathrm{c}}=1.11 \times e^{-5} \text { coulomb }$

6 0

3 years ago

The equation of motion of a particle is s = 2t3 − 8t2 + 4t + 2, where s is in meters and t is in seconds. (assume t ≥ 0.) (a) fi

yaroslaw [1]

The equation of motion of a particle is given by,

s = $2t^{3} - 8t^{2} + 4t +2$

Let velocity of particle is denoted by v.

The velocity of the particle is given by,

velocity (v) = $\frac{ds}{dt}$

v = $\frac{d}{dt} [ 2t^{3} - 8t^{2} + 4t +2 ]$

v = $\frac{d}{dt} 2t^{3} - \frac{d}{dt} 8t^{2} + \frac{d}{dt} 4t + \frac{d}{dt} 2$

v = $6t^{2} -16t +4$

Thus, Velocity of particle is given by,

v = $6t^{2} -16t +4$

Let acceleration of the particle is denoted by a.

The acceleration of particle is given by,

Acceleration = $\frac{dv}{dt}$

a = $\frac{d}{dt} [6t^{2} -16t +4]$

a = $\frac{d}{dt} 6t^{2} -\frac{d}{dt}16t +\frac{d}{dt}4$

a = 12t - 16

Thus, acceleration of the particle is given by,

a = 12t - 16

5 0

3 years ago

On an asteroid, the density of dust particles at a height of 3 cm is ~30% of its value just above the surface of the asteroid. A

melisa1 [442]

Answer:

g = $0.1m/s^2$

Explanation:

From the law of atmosphere

$Nv(y) = n0*e^(-mgy/Kb*T)$

<u>Given:</u>

Kb = Boltzmann's constant = $1.38*10^-23 J/K$

temperature T = 20K

Mass M = 10^-19 kg

Since it is 30% of value above surface, therefore Nv = 0.3n0

Rearranging equation (I) to make g subject of the formula,

g = [ (Kb*T)*in(0.3n0 / n0) ] / (m*y)

Substituting each of the values given in the equation, we obtain

g = $0.1m/s^2$

3 0

4 years ago

On a frozen pond, a 8.54-kg sled is given a kick that imparts to it an initial speed of ð£0=1.87 m/s. The coefficient of kinetic

zhannawk [14.2K]

Answer:2.05 m

Explanation:

Given

Mass of sled $m=8.54 kg$

initial speed $u=0.187 m/s$

coefficient of kinetic Friction $\mu _k=0.087$

According to work-energy theorem work done by all the forces is change in Kinetic energy

$W_{friction}=\frac{1}{2}mv_i^2-\frac{1}{2}mv_f^2$

$\mu _kmg\times d=\frac{1}{2}\times 8.54\times 1.87^2$ ,where d= distance moved

$0.087\times 8.54\times 9.8\times d=14.93$

$d=\frac{14.93}{7.281}$

$d=2.05 m$

4 0

3 years ago