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MA_775_DIABLO [31]
4 years ago
8

Which device in a car helps to protect riders from the effects of inertia in the event of an acident

Physics
2 answers:
Schach [20]4 years ago
5 0
The seatbelt, as it prevents you from flying out of your window.

if this was the appropriate answer make sure to mark as the brainliest!
-procklown
Oksi-84 [34.3K]4 years ago
5 0
The answer to the question is d
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Which element would you expect to gain one electron in a chemical reaction ?
Annette [7]

Answer: Hydrogen

Explanation: Which element would you expect to gain one electron in a chemical reaction ? HYDROGEN

Non-metals are more likely to gain electrons!

***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***

4 0
3 years ago
Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y
Ilia_Sergeevich [38]
Acceleration = (0.2 x g) = 1.96m/sec^2. 
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>

<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
<span>e.g. 75kg = (75 x g) = 735N. </span>
<span>Accelerating force = (735 x 0.2) = 147N</span>
5 0
4 years ago
Read 2 more answers
Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their
Anna35 [415]
Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=\frac{s}{t}
we get
V₁=\frac{100}{10}
V₁=10m/s

V₂=\frac{100}{10.2}
V₂=9.8m/s

V₃=\frac{100}{10.4}
V₃=9.61 m/s

V₄=\frac{100}{10.6}
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
8 0
3 years ago
A trooper is moving due south along the freeway at a speed of 30.1 m/s when a red car passes the trooper. The red car moves with
romanna [79]

Answer:

The correct answer to the following question will be "41.87 m".

Explanation:

The given values are:

The speed of trooper = 30.1 \ m/s

The velocity of red car = 45.4 \ m/s

Now,

A red car goes as far as possible until the speed or velocity of the troops is the same as that of of the red car at

t=\frac{45-30}{2.7}                                                              (∵ time=\frac{distance}{time})

t=5.56 \ sec

then,

The distance covered by trooper,

t1=30\times 5.56+\frac{1}{2}\times 2.7\times (5.56)^2

   =208.33 \ m

The distance covered by red car,

= 45\times 5.56

= 250.2 \ m

Maximum distance = 250.2-208.33

                                = 41.87 \ m                                                        

6 0
3 years ago
A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar
kakasveta [241]

Answer:

W=4037.36\ J

Explanation:

Given:

mass of ice melted, m=3.3\times10^{-2}\ kg

time taken by the ice to melt, t=5\ min=300\ s

latent heat of the ice, L=3.34\times 10^5\ J

Now the heat rejected by the Carnot engine:

Q_R=m.L

Q_R=0.033\times 3.34\times 10^5

Q_R=11022\ J

Since we have boiling water as hot reservoir so:

T_H=373\ K

The cold reservoir is ice, so:

T_L=273\ K

Now the efficiency:

\eta=1-\frac{T_L}{T_H}

\eta=1-\frac{273}{373}

\eta=26.81\%

Now form the law of energy conservation:

Heat supplied:

Q_S-W=Q_R

where:

Q_S= heat supplied to the engine

Q_S-\eta\times Q_S=Q_R

Q_S(1-\eta)=Q_R

Q_S=\frac{11022}{1-0.2681}

Q_S=15059.36\ J

Now the work done:

W=Q_S-Q_R

W=15059.36-11022

W=4037.36\ J

8 0
3 years ago
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