Answer:
0(zero)
Explanation:
Given that
=0.20kg, radius of the bowl,
and that the mass slides from point A to B.
-Since the normal force is perpendicular to the displacement at every point of the motion,then work done by the normal force is zero.
Answer:
a) A = 0.603 m
, b) a = 165.8 m / s²
, c) F = 331.7 N
Explanation:
For this exercise we use the law of conservation of energy
Starting point before touching the spring
Em₀ = K = ½ m v²
End Point with fully compressed spring
=
= ½ k x²
Emo = 
½ m v² = ½ k x²
x = √(m / k) v
x = √ (2.00 / 550) 10.0
x = 0.603 m
This is the maximum compression corresponding to the range of motion
A = 0.603 m
b) Let's write Newton's second law at the point of maximum compression
F = m a
k x = ma
a = k / m x
a = 550 / 2.00 0.603
a = 165.8 m / s²
With direction to the right (positive)
c) The value of the elastic force, let's calculate
F = k x
F = 550 0.603
F = 331.65 N
Answer:
Y_1 = 1.195 m = 119.5 cm
Explanation:
For nth order bright fringe, the distance from the center of the pattern is given by :-

Where,
n = order of nth bright fringe. = 1
wavelength of given light = 
D = distance between the screen and slits. = 3.4 m
and d = separation between the slits. 

Y_1 = 1.195 m = 119.5 cm
Answer: C. The tendency of an object to maintain its state of motion.
Explanation: Newton’s first law: If a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.