Answer:
x = 16
Step-by-step explanation:
SR = ST ⇒ Two sides are equal. So, ΔSRT is an isosceles triangle.
The angles opposite to equal sides are equal.
⇒ ∠STR = ∠R
∠STR = 4x - 28
Linear pair: If a ray stands on a line, then the adjacent angles are supplementary and they are called linear pair
∠STR + ∠STU = 180° {linear pair}
4x - 28 + 9x = 180
4x + 9x - 28 = 180 {Combine like terms}
13x- 28 = 180
Add 28 to both the sides
13x = 180 + 28
13x = 208
Divide both sides by 13
x = 208/13
Hope this helps! Is from the app Photomath.
I can see you come from outside the USA. No insults intended!!
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Anyways, we have to put one side of the ratio and match it to 48.
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Or even better...
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MAKE!!
A!!
PROPORTION!!
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So... Let's say 7 is proportional to 48... so 7/5 = 48/x, where x is the number equivalent to ratio of 5.
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Cross multiply!!
<span>.
</span>7x = 240.
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Divide 7 on both sides.
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x = 34 2/7.
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Hope I helped!!
Complete question:
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?
A) segment a double prime b double prime = segment ab over 2
B) segment ab = segment a double prime b double prime over 2
C) segment ab over segment a double prime b double prime = one half
D) segment a double prime b double prime over segment ab = 2
Answer:
A) segment a double prime b double prime = segment ab over 2.
It can be rewritten as:
Step-by-step explanation:
Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.
We know segment A"B" equals segment AB multiplied by the scale factor.
A"B" = AB * s.f.
Since we are given a scale factor of ½
Therefore,
The equation that explains the relationship between segment AB and segment A"B" is
Option A is correct
Answer:
Step-by-step explanation:
<u>Extended Information </u><u>on</u><u> </u><u>the</u><u> Complex Number System</u>
I am joyous to assist you at any time.
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