Considering that the last 1 in 0.11 is located in the hundredths place, the simplest from of this fraction is 11/100 because it cannot be reduced.

*If you have any questions, feel free to ask me! I'd be happy to help you anytime!

5 0

3 years ago

Read 2 more answers

Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0

lorasvet [3.4K]

Answer:

equation;

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

Center (-4,2)

Radius is

$3 \sqrt{3}$

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

$(x - h) {}^{2} + (y - k) {}^{2} = {r}^{2}$

Where (h,k) is center

r is the radius

So first we group like Terms together

${x}^{2} + 8x + {y}^{2} - 4y - 7 = 0$

Add 7 to both sides

${x}^{2} + 8x + {y}^{2} - 4y = 7$

$( {x}^{2} + 8x) +( {y}^{2} - 4y) = 7$

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

$(\frac{8}{2} ) {}^{2} = 16$

and

$( - \frac{4}{2} ) {}^{2} = 4$

so we have

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 7 + 16 + 4$

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 27$

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

$\sqrt{27} = 3 \sqrt{3}$

So the radius is 3 times sqr root of 3.

8 0

2 years ago

What's the input lol *photo attatched*

marishachu [46]

-20+1= -19
-19/2= -9.5

Check:
-9.5x2= -19
-19-1= -20

3 0

2 years ago

A group of middle school boys have a mean height of 167 cm and a range of 164 cm to 169 cm. A group of high school boys have a m

Alex787 [66]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers