2 years ago

What is the equation of a line that has a slope of 0 and contains the points (4,-3)

Mathematics

1 answer:

Vikentia [17]2 years ago

7 0

You can use point slope form to get this answer

y-y1=m(x-x1)

y--3 = 0(x-4)

y+3=0
y=-3

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3 years ago

1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio

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Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image $(x,y)\rightarrow Image(kx,ky)$

where $k$ represents the scalar factor.

We can find value of $k$ for the given co-ordinates by finding the ratio of $x$ or $y$ co-ordinates of the image and pre-image.

$k=\frac{Image}{Pre-Image}$

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

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As we get $k=5$ for both ratios i.e of $x$ and $y$ co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image $(-2,-7)\rightarrow$ Image $((-2\times5),(-7\times 5))$

Pre-Image $(-2,-7)\rightarrow$ Image $(-10,-35)$ (Answer)

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