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frez [133]
2 years ago
11

2x^2y^5 + 4xy^3 please answer

Mathematics
1 answer:
irina [24]2 years ago
8 0

Answer:

its B, the 2xy3...thingy

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The vertices of a triangle are (-1,3) (6,3) and (-1,-4)
Travka [436]

Answer:

24.5 unit²

Step-by-step explanation:

Area of ∆

= ½ | x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂) |

= ½ | (-1)(3 -(-4)) + 6(-4 -3) + (-1)(3 - 3) |

= ½ | -7 - 42 |

= ½ | - 49 |

= ½ (49)

= 24.5 unit²

<u>Method 2:</u>

Let the vertices are A, B and C. Using distance formula:

AB = √(-1-6)² + (3-3)² = 7

BC = √(-6-1)² + (-4-3)² = 7√2

AC = √(-1-(-1))² + (4-(-3))² = 7

Semi-perimeter = (7+7+7√2)/2

= (14+7√2)/2

Using herons formula:

Area = √s(s - a)(s - b)(s - c)

here,

s = semi-perimeter = (14 + 7√2)/2

s - a = S - AB = (14+7√2)/2 - 7 = (7 + √2)/2

s - b = (14+7√2)/2 - 7√2 = (14 - 7√2)/2

s - c = (14+7√2)/2 - 7 = (7 + √2)/2

Hence, on solving for area using herons formula, area = 49/2 = 24.5 unit²

3 0
2 years ago
Read 2 more answers
Which of the expressions are equivalent to the one below? 7x(6+3)
frosja888 [35]
A. Is the answer
Hope this helped :)
5 0
3 years ago
HELP ILL GIVE BRAINLIEST
Aleksandr-060686 [28]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
A car is moving with a velocity (3.0 m/s) x̂ + (1.0 m/s) ŷ and 3.0 seconds later its velocity is (6.0 m/s) x̂ - (3.0 m/s) ŷ. Wha
Mars2501 [29]

Here we know that the initial velocity of the car is given by:

V_i=(3.0\hat x+1.0\hat y)m/s

And the final velocity of the car is given by:

V_f=(6.0\hat x-3.0\hat y)m/s

It took 3 seconds to attain the final velocity, so we have t=3 s

Therefore, the acceleration can be obtained by:

V_f-V_i=a\times t

a=\frac{V_f-V_i}{t}

Plugging the values of the initial, final velocity and the time, we get:

a= \frac{(6\hat x-3\hat y)-(3 \hat x+1 \hat y)}{3} =\frac{6\hat x-3 \hat y -3 \hat x-1 \hat y}{3} =\frac{3 \hat x-4 \hat y}{3}

So the acceleration of the car is given by:

a=\frac{3 \hat x}{3} -\frac{4 \hat y}{3} =1 \hat x- \frac{4}{3} \hat y

Now we need to find the direction of the average acceleration of the car:

\theta=tan^{-1} \frac{y}{x}

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

\theta=tan^{-1}(\frac{-\frac{4}{3} }{1} )=tan^{-1}(\frac{-4}{3}) =-53.13^\circ

Therefore, the direction of the average acceleration of the car is -53.13^\circ.

8 0
3 years ago
The area of a square lawn is 196 yd2. What is the perimeter of the lawn?
Lesechka [4]

Answer:

The correct answer is 14 yards.

Step-by-step explanation:

Area can be described as a measuring unit to measure the space in any flat surface. The square is a flat surface comprising of four equal sides. Area of a square would be the measure of the length of each size.

As per the question, the area of lawn is 196 yards and it is square shaped. This means that the length of each side would be would be 14 yards.

The area will be calculated by taking the square root of one of the equal sides. The square root of 14 is 196. hence, the correct answer is 14 yards.

- Sophia

8 0
3 years ago
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