Answer:
the time taken for the radioactive element to decay to 1 g is 304.8 s.
Step-by-step explanation:
Given;
half-life of the given Dubnium = 34 s
initial mass of the given Dubnium, m₀ = 500 grams
final mass of the element, mf = 1 g
The time taken for the radioactive element to decay to its final mass is calculated as follows;
![1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s](https://tex.z-dn.net/?f=1%20%3D%20500%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B1%7D%7B500%7D%20%3D%20%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%3D%20log%20%5B%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20log%280.5%29%5C%5C%5C%5C-2.699%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20%28-0.301%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B2.699%20%5Ctimes%2034%7D%7B0.301%7D%20%5C%5C%5C%5Ct%20%3D%20304.8%20%5C%20s)
Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.
12. The answer is 12 because two x 6 is twelve awesome
Answer:
Step-by-step explanation:
Red = 6
Blue = 3
Green = 5
Total = 14
First marble = 6/14 = 3/7 You now have 5 reds and 13 total
Second Marble = 5 * 13 which brings you down to 4 red and 12 total.
Third Marble = 4/12 = 1/3
Result
P(3 Red) = 3/7 * 5/13 * 1/3 cancel the 3s
P(3 Red) = 1/7 * 5/13
P(3 Red) = 5/91
P(3 Red) = 0.0549 . Rounding to the nearest 1/100 depends on what you have been told about rounding. I would say the answer is 0.05 but your teacher may say something different.
<span>A rectangular soccer field is twice as long as it is wide. If the perimeter of the soccer field is 300 yards , what are its dimensions?
I know the basic formula is 2W+2L=300 but i am not sure where to go from there...
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Equations:
2W + 2L = 300
L = 2W
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Substitute for "L" and solve for "W":
</span><span>2W + 2(2W) = 300
6W = 300
W = 50 yds (width)
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Solve for "L":
L = 2W
L = 100 yds (length)
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Cheers.
</span>
The HA Theorem is a special case of the AAS postulate.
