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blagie [28]
3 years ago
11

Wesimann Co. Issued 13-year bonds a year ago at a coupon rate of 7.3 percent. The bonds make semiannual payments and have a par

value of $1,000. If the YTM on these bonds is 5.6 percent, what is the current bond price?
Mathematics
1 answer:
Harman [31]3 years ago
8 0

Answer:

Current Bond price = $1155.5116

Step-by-step explanation:

We are given;

Face value; F = $1,000

Coupon payment;C = (7.3% x 1,000)/2 = 36.5 (divided by 2 because of semi annual payments)

Yield to maturity(YTM); r = 5.6%/2 = 2.8% = 0.028 (divided by 2 because of semi annual payments)

Time period;n = 13 x 2 = 26 years (multiplied by 2 because of semi annual payments)

Formula for bond price is;

Bond price = [C × [((1 + r)ⁿ - 1)/(r(r + 1)ⁿ)] + [F/(1 + r)ⁿ]

Plugging in the relevant values, we have;

Bond price = [36.5 × [((1 + 0.028)^(26) - 1)/(0.028(0.028 + 1)^(26))] + [1000/(1 + 0.028)^(26)]

Bond price = (36.5 × 18.2954) + (487.7295)

Bond price = $1155.5116

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Answer:

1) $242.47

2) \frac{5}{27}

3) $1.63

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Tan(x)=2
nydimaria [60]
<span>Tan(x)=2
Or for x=45 tan(x)=1
then for tan(x)=2 ; x must be superior to 45 
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8 0
3 years ago
Kevin and Randy Muise have a jar containing 80 ​coins, all of which are either quarters or nickels. The total value of the coins
SCORPION-xisa [38]

Answer:

  • 39 quarters and 41 nickels

Step-by-step explanation:

Let the number of quarters be x and nickels be y.

<u>Given:</u>

  • Quarter is 25 cents
  • Nickel is 5 cents
  • Number of coins is 80
  • Total amount is $11.80 = 1180 cents

<u>We have equations:</u>

  • x + y = 80
  • 25x + 5y = 1180

<u>Solve the system by elimination, subtract 5 times the first equation from the second one:</u>

  • 25x + 5y - 5x - 5y = 1180 - 80*5
  • 20x = 780
  • x = 780/20
  • x = 39

<u>Find the value of y:</u>

  • 39 + y = 80
  • y = 80 - 39y = 41

<u>Verify:</u>

  • 25*39 + 5*41 = 975 + 205 = 1180
7 0
2 years ago
What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
3 years ago
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