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3 years ago

Complete the factoring, 5x^2 - 40x = 5x( ) HELP ASAP PLS!

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

8 0

Answer:

$5x(x-8)$

Step-by-step explanation:

Factor $5x$ out of $5x^{2} -40x$

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The sum of two numbers is less than 2. If we subtract the second number from the first, the difference is greater than 1. What a

Anna007 [38]

Answer:

the value of these two numbers are 1/2 and 3/2

Step-by-step explanation:

Given that:

x+y < 2 ---- (1)

y - x > 1 ---- (2)

From equation (2), let y > 1 + x then substitute it into equation (1)

x + 1 + x < 2

2x + 1 < 2

2x < 2 - 1

2x < 1

x < 1/2

From equation (2), replace the value of x to be 1/2

y - 1/2 > 1

y > 1 + 1/2

y > 3/2

5 0

3 years ago

There are 42 different types of ice cream at the grocery store the probability that ice cream selected at random has chocolate i

Alex787 [66]

Answer:

Step-by-step explanation:

42-42(2/7)

42-12

There are 30 options with no chocolate.

3 0

3 years ago

Find the tenth term of the expansion (x+ y)¹³

Anon25 [30]

Answer:

$715x^4y^9$

Step-by-step explanation:

Given

$(x + y)^{13$

Required

Determine the 10th term

Using binomial expansion, we have:

$(a + b)^n = ^nC_0a^nb^0 + ^nC_1a^{n-1}b^1 + ^nC_2a^{n-2}b^2 +.....+^nC_na^{0}b^n$

For, the 10th term. n = 9

So, we have:

$(a + b)^n = ^nC_{9}a^{n-9}b^{9$

$(x + y)^{13} = ^{13}C_{9}x^{13-9}y^9$

$(x + y)^{13} = ^{13}C_{9}x^4y^9$

Apply combination formula

$(x + y)^{13} = \frac{13!}{(13-9)!9!}x^4y^9$

$(x + y)^{13} = \frac{13!}{4!9!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10*9!}{4!9!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10}{4!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10}{4*3*2*1}x^4y^9$

$(x + y)^{13} = \frac{17160}{24}x^4y^9$

$(x + y)^{13} = 715x^4y^9$

Hence, the 10th term is $715x^4y^9$

3 0

3 years ago

Can somebody help with numbers 19-24

Gemiola [76]

19-20 idk but ik the others
21.)0.785
22.)0
23.)-14.5
24.)7.838

5 0

3 years ago

A company that manufactures memory chips for digital cameras uses the formula c equals 120 cube root of n squared end root plus

Galina-37 [17]

Answer:

$6062

Step-by-step explanation:

The formula we are given is

$c=120\sqrt[3]{n^2}+1300$

We will replace n with 250:

$c=120\sqrt[3]{250^2}+1300\\ \\=120\sqrt[3]{62500} +1300\\\\=120(39.685)+1300\\\\=4762.20+1300\\\\=6062.20 \approx 6062$

8 0

4 years ago

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