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nexus9112 [7]
3 years ago
10

Suggest 2 reasons why copper should not be disposed in landfill sites

Chemistry
2 answers:
lidiya [134]3 years ago
8 0
It's a reliable source to many of products and it's value is far to hight to simply abandoned
SIZIF [17.4K]3 years ago
6 0
Because it's a waste. And it's medal instead of disposing just reuse it and also it can affect people  Like high exposure of copper can be dangerous 
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Atoms join together to form compounds bt gaining,loosing or sharing ​
user100 [1]

Answer:

the answer is C) sharing

Explanation:

positive ions & negative ions form when atom s lose or gain electrons. Covalent bonds form when atoms share electrons.Metallic bonds form by the attraction of metal ions and the electrons around them. Covalent compounds form when atoms of elements share electrons.

4 0
3 years ago
Read 2 more answers
Calculate the number of grams of oxygen required to convert 48.0 g of glucose to co2 and h2o.
worty [1.4K]

I believe that the balanced chemical reaction is:

C6H12O6 + 6 O2 → 6 CO2 + 6 H2O 

 

So the number of grams of oxygen required is:

mass O2 required = 48 g C6H12O6 * (1 mole C6H12O6 / 180.16 g) * (6 mole O2 / 1 mole C6H12O6) * (32 grams O2 / 1 mole)

<span>mass O2 required = 51.15 grams</span>

4 0
3 years ago
D
maksim [4K]

Answer:

can you provide a picture?

7 0
3 years ago
The conductance of the electric current through the electrolytic solution increases with
zheka24 [161]

The conductance of the electric current through the electrolytic solution increases with increase in concentration.

<h3>What is electrolytic solution?</h3>

Electrolytic solutions are solutions that are capable of conducting an electric current due to presence of ions.

The current flowing in an Electrolytic solutions is calculated as;

Q = It

I = Q/t

where;

  • Q is charges

Increase in the concentration of the charges, increases the amount of charges in the solution and hence the conductance of the solutions will increase as well.

Learn more about Electrolytic solutions here: brainly.com/question/14654936

#SPJ1

7 0
2 years ago
Estimate the molar mass of a gas that effuses at 1.80 times the effusion rate of carbon dioxide. answer in units of g/mol.
Effectus [21]
From Grahams Law the rates of effusion of two gases are inversely proportional to the square roots of their molar masses at the same temperature and pressure.
Therefore; R1/R2 = √mm2/√mm1
The molecular mass of Carbon dioxide is 44 g
Hence;  1.8 = √(44/x
             3.24 = 44/x
                x = 44/3.24
                   = 13.58 
Therefore, the molar mass of the other gas is 13.58 g/mol
           
3 0
3 years ago
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