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s2008m [1.1K]
2 years ago
15

What is the molarity of a salt solution made by dissolving 250.0 grams of NaCl in 775 mL of solution?

Chemistry
1 answer:
tester [92]2 years ago
7 0

The molarity of a salt solution made by dissolving 250.0 grams of NaCl in 775 mL of solution is <u>5.52 M</u> .

<u>Explanation:</u>

The molarity of a solution tells one how many moles of <u>solute</u> one can get <em>per liter</em> of solution.One should remember to must convert this volume to liters by using the conversion factor:

1 L = 10³ml

Sodium chloride (NaCl) has a molar mass of 58.44 g per mol , which means that the sample will contain:

   250 \mathrm{g} \times \frac{1 \text { mole of } \mathrm{Nacl}}{58.44 \mathrm{g}}=4.278 \text { mole of } \mathrm{Nacl}

This means that the molarity of the solution will be:

\text {Molarity,c}=\frac{n_{\text {solute}}}{V_{\text {solution }}}=\frac{4.28}{775 \times 10^{-3}}=0.00552 \times 10^{3}=5.52 M

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Are solar and lunar eclipses processed by the movements of the Earth and moon?
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Explanation:

As the Earth rotates on its axis and revolves around the Sun, several different effects are produced. When the new moon comes between the Earth and the Sun along the ecliptic, a solar eclipse is produced. When the Earth comes between the full moon and the Sun along the ecliptic, a lunar eclipse occurs.

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What is the density of ethane gas, C2H6 at STP
yawa3891 [41]

Answer:

The answer is that ethane gas has a density of 1.34 g/L at STP

Explanation:

Ethane weighs 0.0013562 gram per cubic centimeter or 1.3562 kilogram per cubic meter, i.e. density of ethane is equal to 1.3562 kg/m³; at 0°C (32°F or 273.15K) at standard atmospheric pressure.

7 0
2 years ago
A car travels 350 km in 7 hours. What is the average speed of the car (in km/hr)?
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50 km/hr

Explanation:

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7 0
3 years ago
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Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
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