All categories

2 years ago

What is the molarity of a salt solution made by dissolving 250.0 grams of NaCl in 775 mL of solution?

Chemistry

1 answer:

tester [92]2 years ago

7 0

The molarity of a salt solution made by dissolving 250.0 grams of NaCl in 775 mL of solution is 5.52 M .

Explanation:

The molarity of a solution tells one how many moles of solute one can get per liter of solution.One should remember to must convert this volume to liters by using the conversion factor:

1 L = 10³ml

Sodium chloride (NaCl) has a molar mass of 58.44 g per mol , which means that the sample will contain:

$250 \mathrm{g} \times \frac{1 \text { mole of } \mathrm{Nacl}}{58.44 \mathrm{g}}=4.278 \text { mole of } \mathrm{Nacl}$

This means that the molarity of the solution will be:

$\text {Molarity,c}=\frac{n_{\text {solute}}}{V_{\text {solution }}}=\frac{4.28}{775 \times 10^{-3}}=0.00552 \times 10^{3}=5.52 M$

You might be interested in

What is the most striking part of this simulation?

oee [108]

None of the alpha particles fired at the foil are being repelled back, like they were in the Rutherford atom simulation.I hope this correct.

3 0

3 years ago

How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal? Show all o

Sladkaya [172]

Potassium 23.5g/39.0983g/mol = 0.601mol

The Ratio of reactants is 2 to 1 so (0.601mol)/2 = 0.3005mol

Therefore 0.3005mol of F2 is needed to find liters use

formula V = nRT/P (V)Volume = 22.41L

(T)Temperature = 273K or 0.0 Celsius

(P)Pressure = 1.0atm

(R)value is always .08206 with atm n = 0.3005moles (273)(.08206)(0.3005)/1 = V V = 6.7319 Liters

8 0

3 years ago

Read 2 more answers

Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:

Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

$\frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} )$ ,

where λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from $n_1$ to $n_2$ and $R_h$ = 109677 is the Rydberg Constant. Here $n_1$ and $n_2$ represents the transitions.

(a) $n_1$ =2 to $n_2$ = infinity

$\frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2} )$ = 109677/4 [since 1/infinity = 0] Therefore, $\lambda$ = 4 / 109677 = 0.00003647 m

(b) $n_1$ =4 to $n_2$ = 20

$\frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2} )$ = 6580.62

Therefore, $\lambda$ = 1 / 6580.62 = 0.000152 m

(c) $n_1$ =3 to $n_2$ = 10

$\frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2} )$ = 11089.56

Therefore, $\lambda$ = 1 / 11089.56 = 0.00009 m

(d) $n_1$ =2 to $n_2$ = 1

$\frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2} )$ = - 82257.75

Therefore, $\lambda$ = 1 /82257.75 = - 0.0000121 m

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

8 0

1 year ago

If the % acetic acid listed on a vinegar bottle is 4%, what is the implied uncertainty of the acetic acid concentration

Tom [10]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete because the data provided only makes it possible to calculate the certainty of the acetic acid content per total volume of the vinegar. Thus, the 4% means for every 100 mL of the vinegar, there is 4 mL of acetic acid present. To calculate the volume of acetic acid in any other volume of vinegar, the formula will be

volume of acetic acid = 4/100 × total volume of vinegar

6 0

2 years ago

Why does a can of diet cola float in water but a can of regular cola does not

maria [59]

Answer:

because there more acid in diet cola

7 0

2 years ago