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s2008m [1.1K]
3 years ago
15

What is the molarity of a salt solution made by dissolving 250.0 grams of NaCl in 775 mL of solution?

Chemistry
1 answer:
tester [92]3 years ago
7 0

The molarity of a salt solution made by dissolving 250.0 grams of NaCl in 775 mL of solution is <u>5.52 M</u> .

<u>Explanation:</u>

The molarity of a solution tells one how many moles of <u>solute</u> one can get <em>per liter</em> of solution.One should remember to must convert this volume to liters by using the conversion factor:

1 L = 10³ml

Sodium chloride (NaCl) has a molar mass of 58.44 g per mol , which means that the sample will contain:

   250 \mathrm{g} \times \frac{1 \text { mole of } \mathrm{Nacl}}{58.44 \mathrm{g}}=4.278 \text { mole of } \mathrm{Nacl}

This means that the molarity of the solution will be:

\text {Molarity,c}=\frac{n_{\text {solute}}}{V_{\text {solution }}}=\frac{4.28}{775 \times 10^{-3}}=0.00552 \times 10^{3}=5.52 M

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A block of wood has the mass of 180 grams.it is 10 cm long,6 cm wide and 4 cm thick.what is it’s density?
DochEvi [55]

Answer:

0.75 g/cm³

Explanation:

Given data:

Mass of wooden block =  180 g

Length of block = 10 cm

Width of block = 6 cm

Height or thickness = 4 cm

Density of block = ?

Solution:

Volume of block = height × length × width

Volume of block = 4 cm × 10 cm× 6 cm

Volume of block = 240 cm³

Density of block:

density = mass/ volume

d = 180 g/ 240 cm³

d = 0.75 g/cm³

4 0
3 years ago
In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
zloy xaker [14]

Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

3 0
3 years ago
why can the combined weights of several liquids mixed in an open flask be less than but never more than the sum of all the weigh
nexus9112 [7]
Because you are never adding more than the substances created, nor are you creating any, but should a chemical reaction take place you could see the liquid change form into a gaseous state and that would result a loss of the liquid volume.
So to wrap it all up you can’t have more liquids than what is already there but you could always lose some due to a chemical change, hence the reason it says an open flask, the chemical change would not be collected, mass would be lost
4 0
3 years ago
Le Chatelier's Principle. For the reaction below, if the equilibrium concentrations were NH3 = 2 x 10-4, H3O+ = 2 x 10-4M and NH
telo118 [61]

Answer:

Explanation:

NH3 + H3O+ --> NH4+ + H2O

equllibrium constant =K = [ H2O] [NH4+] / [NH3] [H3O+ ]

                                      =

by inserting thier respecive values can you calcaulte, by the way coniseder  [ H2O] =1 ,

6 0
3 years ago
A 1.00 L flask is filled with 1.15 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pres
tatiyna

Answer:

The partial pressure of argon in the flask = 71.326 K pa

Explanation:

Volume off the flask = 0.001 m^{3}

Mass of the gas = 1.15 gm = 0.00115 kg

Temperature = 25 ° c = 298 K

Gas constant for Argon R = 208.13 \frac{J}{kg k}

From ideal gas equation P V = m RT

⇒ P = \frac{m R T}{V}

Put all the values in above formula we get

⇒ P = \frac{0.00115}{0.001} × 208.13 × 298

⇒ P = 71.326 K pa

Therefore, the partial pressure of argon in the flask = 71.326 K pa

4 0
3 years ago
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