Traveling miles on this taxi costs
In fact, we spend 2.50 no matter what, and then we add 3.25 (i.e. the cost of a mile) multiplied by the number of miles.
This quantity has to be less than or equal to 61, so we have
Solving for , we start by subtracting 2.5 from both sides:
Then, we divide both sides by 3.25:
Please consider the graph.
We have been given that graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic. We are asked to choose the weights, which are within 2 standard deviations of the mean.
We can see from our graph that mean of the weights is 9.5 and standard deviation in 0.5.
The data point that would be below two standard deviation is: that is
.
The data point that would be above two standard deviation is: that is
.
Now we need to check the data points that lie within 8.5 and 10.5.
Upon looking at our given choices, we can see that 8.9, 9.5 and 10.4 pounds lie within 2 standard deviation of the mean.
Therefore, 8.9 lbs, 9.5 lbs and 10.4 lbs are correct choices.
