Answer:
Approximately 12,500 SARS-CoV-2 viruses
Explanation:
According to this question, the period described is 1mm in diameter. Since 1millimetre(mm) is 1000metre(m), this means that the period is 0.001m in diameter.
Also, the SARS-CoV-2 virus has a diameter of 80 nm (1nm = 10^9m).
Since 10^6nanometres (nm) or 1,000,000nm makes 1millimeter (mm), 80nm of the virus will be:
= 80/1,000,000
= 0.000080mm or 8 × 10^-5mm
To calculate how many of the SARS-CoV-2 virus will fit into the period, we divide the diameter of the period (in mm) by the diameter of the virus (in mm).
That is; 1 ÷ 8 × 10^-5
= 1/8 × 10^5
= 0.125 × 100,000
= 12,500
Therefore, approximately 12500 SARS-CoV-2 viruses will fit in the period.
