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Elis [28]
4 years ago
11

The sum of three integers is 228. The second integer is 1 more than the first, and the third integer is 2 more than the first. W

rite and equation to determine the integers
Mathematics
1 answer:
MaRussiya [10]4 years ago
7 0
Ok so to start, your unknown numbers will ne represented as x. The equation looks like this: x+x+1+x+2=228. You have your unknown number, the number plus one, and the numner plus two. To find the answer you divide 228 by 3. Those numbers are all equal though,so you play around with them until you get 75+75+1+75+2=228
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Hamid has gained weight. He now weights 88kg, which is 10% higher than his normal weight. What is Hamids normal weight
zubka84 [21]

Let his normal weight = 100%

He is 10% more so he is 110%

Divide his weight now by 110% to find his normal weight.

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$535.25

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8 0
3 years ago
PLEASE HELP AND ANSWER!!!!! Which of the following reveals the minimum value for the equation 2x2 + 12x − 14 = 0?
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Answer:

The correct option is 3.

Step-by-step explanation:

The given equation is

2x^2+12x-14=0

It can be written as

(2x^2+12x)-14=0

Taking out the common factor form the parenthesis.

2(x^2+6x)-14=0

If an expression is defined as x^2+bx then we add (\frac{b}{2})^2 to make it perfect square.

In the above equation b=6.

Add and subtract 3^2 in the parenthesis.

2(x^2+6x+3^2-3^2)-14=0

2(x^2+6x+3^2)-2(3^2)-14=0

2(x+3)^2-18-14=0

2(x+3)^2-32=0             .... (1)

Add 32 on both sides.

2(x+3)^2=32

The vertex from of a parabola is

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If a>0, then k is minimum value at x=h.

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The equation 2(x+3)^2=32 reveals the minimum value for the given equation.

Therefore the correct option is 3.

5 0
3 years ago
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