Answer:
A) 300
B) 3:1
C) 9 long yellow : 3 long green : 3 short yellow : 1 short green
Explanation:
Long stems (L_) are dominant to short stems (ll)
Yellow seeds (Y_) are dominant to green seeds (yy)
We interbred pea plants with long stems and yellow seeds (L_Y_), but they had a short green parent (llyy) that could have only produced <em>ly</em> gametes, so our plants are heterozygous <em>LlYy</em>.
C) We interbred them LlYy x LlYy. If the two genes are unlinked, this is a typical dihybrid cross and from Mendel's law of independent assortment we know that the offspring will have the following phenotypic ratios:
- 9/16 L_Y_ (Long, yellow)
- 3/16 L_yy (Long, green)
- 3/16 llY_ (short, yellow)
- 1/16 llyy (short, green)
A) 3/16 × 1600 = 300 plants will be long and green.
B)
9/16 + 3/16 = 12/16= 3/4 plants will be yellow;
3/16 + 1/16 = 4/16= 1/4 plants will be green.
The ratio will be 3 yellow : 1 green
D.
when revising your professional development plan
Answer:During interphase, the cell grows and DNA is replicated. During the mitotic phase, the replicated DNA and cytoplasmic contents are separated, and the cell divides. ... During interphase, the cell grows and the nuclear DNA is duplicated. Interphase is followed by the mitotic phase.
Explanation:
Invasive species is the easiest way to answer this, with invasive species the diversity will likely decrease
The type b intercalated cells will reduce the amount of bicarbonate ion secreted and the amount of hydrogen ions excreted by the body in order to deal with alkalosis.
<h3>What is alkalosis?</h3>
Alkalosis is a condition in which excess alkali is present in the blood.
Alkalosis occurs when the body exceeds excess alkali in from the body.
Therefore, the type b intercalated cells will reduce the amount of bicarbonate ions secreted and the amount of hydrogen ions excreted by the body in order to deal with alkalosis.
Learn more about alkalosis at: brainly.com/question/14971300
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