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lord [1]
3 years ago
11

I need help with this worksheet too pls

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0
6.M angle 2 =46. M angle 1 = 134
7.M angle 1 =125. M angle 2 =55
8. M angle 1 and M angle 2 both equal
103
Sorry for not answering the rest I’m lazy rn
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The box plot represents the distribution of test scores for 24 students. None of the students
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50% of the scores are between 65 and 88

Step-by-step explanation:

taking the diagnostic too

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What is the value of X?<br><br> (x + 11)<br> (3x + 7)
kolbaska11 [484]

Answer:

im not sure if this is correct but:

Step-by-step explanation:

4x+18

360= 4x+18

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4 0
4 years ago
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2. Lab groups of three are to be randomly formed (without replacement) from a class that contains five engineers and four non-en
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Answer:

The number of different lab groups possible is 84.

Step-by-step explanation:

<u>Given</u>:

A class consists of 5 engineers and 4 non-engineers.

A lab groups of 3 are to be formed of these 9 students.

The problem can be solved using combinations.

Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.

The combination of <em>k</em> items from <em>n</em> items is: {n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of different lab groups possible as follows:

The number of ways of selecting 3 students from 9 is = {n\choose k}={9\choose 3}

                                                                                         =\frac{9!}{3!(9 - 3)!}\\=\frac{9!}{3!\times 6!}\\=\frac{362880}{6\times720}\\ =84

Thus, the number of different lab groups possible is 84.

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3 years ago
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A scholarship would be an example of a cash ____ .
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The answer would be 1)
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3 years ago
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