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daser333 [38]
3 years ago
10

Use the drop-down menus to complete the proof. Given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the . Therefore,

m∠1 = m ∠5 by the definition of congruent. We also know that, by definition, ∠3 and ∠1 are a linear pair so they are supplementary by the . By the , m∠3 + m ∠1 = 180. Now we can substitute m∠5 for m∠1 to get m∠3 + m∠5 = 180. Therefore, by the definition of supplementary angles, ∠3 and ∠5 are supplementary.

Mathematics
2 answers:
zaharov [31]3 years ago
5 0

Answer:

corresponding angles theorem

linear pair postulate

definition of supplementary angles

Step-by-step explanation:

ololo11 [35]3 years ago
4 0

Answer:

From the graph attached, we know that \angle 1 \cong \angle 5 by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like \angle 1 and \angle 5.

We also know that, by definition of linear pair postulate, \angle 3 and \angle 1 are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that \angle 3 and \angle 1 together are 180°, because they are on a straight angle. That is, m \angle 3 + m \angle 1 = 180\°

If we substitute \angle 5 for \angle 1, we have m \angle 3 + m \angle 5 = 180\°, which means that \angle 3 and \angle 5 are also supplementary by definition.

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What happens to the graph of the line y = mx + b if the value of b is decreased?
ollegr [7]

Answer:

The lines moves lower.

Step-by-step explanation:

The steepness of a line is related to the slope, m.

b is the y-intercept, not the slope.

b is where the line intersects the y-axis.

Changing b changes the vertical position of the line.

Answer: The lines moves lower.

7 0
2 years ago
Sophia exchanged 1,000 US dollars for the south African currency. the exchange rate was 7.15 rand to $1.00.
mel-nik [20]
1 / 7.15 = 1000 / x......$ 1 to 7.15 rand = $ 1000 to x rand
cross multiply because this is a proportion
(1)(x) = (7.15)(1000)
x = 7150 <=== Sophia got 7150 rand
5 0
3 years ago
grandma gigi gave leyla a rare purple stone for her sweet 16 birthday. at that time,the stone was worth$245. it has been increas
sergij07 [2.7K]
This is a compound interest problem, therefore s(t) should be in the form:
s(t) = a(r)^{t}

where: 
t = time in years
s(t) = the value of your item after t years
a = the initial value of your item
r = rate

Therefore, we already know that a = 245$.

Now, we can calculate r:
r^{t}=\frac{s}{a}
r =  \sqrt[t]{ \frac{s}{a} }
r = \sqrt[5]{ \frac{560.50}{245} }
     = 1.18

Therefore, the correct answers are a = 245 and r = 1.18

4 0
3 years ago
The population of a town is 63,555. The land area of the town is 3.1 km².
lara31 [8.8K]
I think it might be this answer <span> 20501.6 </span>
8 0
3 years ago
Read 2 more answers
Find a fraction equivalent to 5/7 whose squared terms add up to 1184.
bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y  } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}

                                                              \large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \  \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28  } \end{gathered}$}

                                                                  \large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20  } \end{gathered}$}

The fraction that satisfies the request is \bf{\dfrac{20}{28}} , since in \bf{\dfrac{-20}{-28}} the negative signs are canceled and the first fraction is obtained.

3 0
2 years ago
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