See the diagram below.

is the height, and

is the slant height.
The height is the distance from the
base of the pyramid to the vertex (the top of the pyramid). It runs perpendicular to the base.
The slant height is the distance from the
base of the triangles which make up its sides to the vertex. It runs perpendicular to this base as well.
All reals is the answer.
Since y =-9 graph is way below the absolute value graph. Meaning that y value of modulus is greater than the constant graph.
Answer: x = 184°
Step-by-step explanation: As we can see in the figure below, angles 2 and 4 are <u>Vertical</u> <u>Angles</u>, i.e., they are angles opposite each other when two lines cross. Vertical angles are always congruent.
Then,
m∠2 = m∠4


Value of x is

x = 184
The value of x is 184°.
Answer:
10010
Step-by-step explanation:


So
gives us:



-----------------------------------------------------
Combine like terms:


We aren't allowed to have a coefficient bigger than 1.
I'm going to replace
with 1 and
with
:

I want a
number:

Combine like terms:

:

Combine like terms:

We can rewrite the first term by law of exponents:


So the binary form is:

Maybe you like this way more:
Keep in mind 1+1=10 and that 1+1+1=11:
Setup:
1 0 1 1
+ 1 1 1
------------------------------
(1) (1) (1)
1 0 1 1
+ 1 1 1
------------------------------
1 0 0 1 0
I had to do some carry over with my 1+1=10 and 1+1+1=11.
3.21 it should be at least