Question

Someone please help me!

Answer 1

Answer:

A. $x \leq -16$  

B. b > 11

C. $c \leq -13$

D. $x \geq -9$

Step-by-step explanation:

Given the following algebraic expression;

A. $\frac {3x}{4} \leq 12$

We would simplify the equation by multiplying all through by 4;

$4 * \frac {-3x}{4} \leq 12 * 4$

$-3x \leq 48$

Divide both sides by -3;

$x \leq -16$

B. 5b - 28 > 27

Rearranging the equation, we have;

5b > 27 + 28

5b > 55

Divide both sides by 5

b > 11

C. $13c \leq -169$

Divide both sides by 13

$c \leq -13$

D. $3x - 7 \geq 4x + 2$

Collecting like terms, we have;

$3x - 4x \geq 2 + 7$

$-x \geq 9$

Divide both sides by -1

$x \geq -9$