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krok68 [10]
3 years ago
7

Did I set up the equation right? Please help me.​

Mathematics
1 answer:
andrezito [222]3 years ago
5 0

Yes you did a little reminder for you from me is that c^2 will ALWAYS be across from the right angle(90 degree)

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Step-by-step explanation:

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Which quadratic function has a wider graph than y=2x^2?
Trava [24]

Answer:

y = 1/2 x²

Step-by-step explanation:

The coefficient of the first term in a quadratic, in our case here, x², will tell us how the graph stretches. This is akin to the slope within the linear graph. Similar to the slope, the smaller the coefficient value, or value of slope m, the shallower the angle.

When discussing quadratics, the larger the coefficient of our x² term, the steeper, and skinnier the graph. If we want to look for a graph that is wider than y = 2x², then we need to find a graph with a coefficient that is less than 2.

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y = 1/2 x²

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3 years ago
Find the coordinates of the midpoint of a line segment with end points (-3,4) and (7,9)
lesantik [10]

Answer:  (2, 6.5)

<u>Step-by-step explanation:</u>

Midpoint_{x,y}=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{-3+7}{2},\dfrac{4+9}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{4}{2},\dfrac{13}{2}\bigg)\\\\\\.\qquad \qquad \quad=\large\boxed{(2,6.5)}

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Esitmate 242 PLEASEEEEEEEEE I NEED THIS
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Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Help with this question.
pychu [463]

Answer:

angleS=83^o

angleR=23^o

Step-by-step explanation:

<h3><u>The Law of Sines</u></h3>

The Law of Sines states that for a given triangle (in a plane), the ratio formed by the Sine of any one of the three interior angles and the side across from it is equal to a common number.

If a triangle is drawn in standard form, with the three vertices identified as A, B, and C, and the interior angles at each vertex simply identified as angleA, angleB, angleC, the sides across from those angles are identified as a, b, and c, respectively.  Given such a labeling for a triangle, the Law of Sines gives the following equation:

\frac{sin(angleA)}{a} =\frac{sin(angleB)}{b} =\frac{sin(angleC)}{c}

From the picture you presented, with triangle RST, side r is on the right and unlabeled, side s is shown in red, and side T is shown in green.  The interior angles for R and S are unlabeled, and angle T is defined as 74 degrees.  The Law of Sines would give the following relationship for your triangle:

\frac{sin(angleR)}{r} =\frac{sin(angleS)}{s} =\frac{sin(angleT)}{t}

Substituting known values...

\frac{sin(angleR)}{r} =\frac{sin(angleS)}{12.7ft} =\frac{sin(74^{o} )}{12.3ft}

It should be noted that without information about the length of side r, angle R cannot be found directly with the Law of Sines because that portion of the equation holds two unknowns.  However, if the other two angles of the triangle are known, angle R can be solved for by using the Triangle Sum Theorem.

<h3><u>Finding Angle S</u></h3>

Focusing in on the ratio with known values on the far right, and the ratio containing angleS first:

\frac{sin(angleS)}{12.7ft} =\frac{sin(74^{o} )}{12.3ft}

... multiplying both sides of the equation by 12.7 ft...

sin(angleS) =\frac{sin(74^{o} ) * 12.7ft}{12.3ft}

Note that the right side of the equation has units of feet in both the numerator and denominator (with no addition or subtraction), so the units will cancel.  Simplifying the right side of the equation by evaluating the expression in a calculator (make sure you're in "degree" mode), will yield a unit-less number:

sin(angleS) = .9925222389...

Undoing the sine function, and solving for the measure of angle S will require taking the "arcsin" of both sides of the equation...

arcsin(sin(angleS))=arcsin(0.9925222389...)\\angleS=arcsin(0.9925222389...)\\angleS=82.98876661...^o\\angleS=83^o<u />

<u />

<h3><u>Finding Angle R</u></h3>

Knowing both angleS and angleT, we can apply the Triangle Sum Theorem to solve for angle R.

Triangle Sum Theorem:  The sum of all 3 interior angles in a triangle (in a plane) is 180 degrees.

angleR+angleS+angleT=180^o\\angleR+83^o+74^o=180^o

Using the subtraction property of equality to isolate angleR and combining like terms...

angleR=180^o-83^o-74^o\\angleR=23^o

8 0
1 year ago
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