The figure below shows two pair of congruent triangles. ΔRBO ≅ ________. ΔPAT ΔATP ΔPTA ΔAPT

Mathematics

1 answer:

o-na [289]2 years ago

3 0

Answer:

is there a picture you could add i can answer the question more efficiently if you do.(bc i am aloud to edit my responce)thanks!

Step-by-step explanation:

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I really need help if anyone can help that would be great

Oliga [24]

Factor the denominator:

(3x-1)(x+2)

every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.

since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.

the answer here is C.

5 0

3 years ago

TIME REMAINING

ollegr [7]

Answer:

(b) (x -10)(x +10)

Step-by-step explanation:

The factorization of the difference of squares is a special form:

a² -b² = (a -b)(a +b)

<h3>Application</h3>

Your expression is recognizable as the difference of squares:

x² -100 = x -10²

Using the above form, the factorization is ...

= (x -10)(x +10) . . . . . . . . matches the second choice

7 0

1 year ago

a class of 54 students is divided into equal groups for orientation each group should have at least 7 students but no more than

Dennis_Churaev [7]

2 students more were introducced in the class and each group had 8 people

8 0

2 years ago

There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$