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lord [1]
3 years ago
6

Wouldnt it be 15??? I would guess so. Katie keeps deleting this but Im not sure why. Sorry katie but I really need help

Mathematics
2 answers:
Anna007 [38]3 years ago
3 0

Answer:

25 in; C

Step-by-step explanation:

Hey!

There probably is a reason she is deleting. You could contact her or ask some help elsewhere.

Anyway! I'm trying to get this in fast. (Remember the Pythagorean Theorem?) That will be very useful here since it is a right triangle.

<u>L² + L² = H² (or H² - L² = L²):</u>

In that case, we'll use the second one because our Hypotenuse is given.

We can substitute each value of the numbers:

65² - 60² = L²

Evaluating:

4225 - 3600 = 625

√625 = 25 inches

Thusly, the third side would be \boxed{25{\text{\:inches\:or\:C.}}}

<em>Also note we could have simplified into a Pythagorean Triple. This method is a simpler more basic method for learning the concept.</em>

Hope this helps!

Zigmanuir [339]3 years ago
3 0

Answer:

25 inches.

Explanation:

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Anarel [89]

Answer:

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Step-by-step explanation:

We can start by distributing the 2 to each term in the parentheses...

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7 0
2 years ago
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damaskus [11]
The answer is 11/36

2/12 chance of rolling fours

because there are 2 sides containing a four on both dice combined and 12 sides in total.

Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.

I personally like to imagine a box like this:
_ _ _ _ _ _
|
|
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.

1/6 * 1/6 = 1/36 chance to roll double of ones

And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:

1/36 * 5 = 5/36

So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:

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5 0
2 years ago
Please please please I'm begging you help me find the y intercept for these I will give brainliest
konstantin123 [22]

Answer:

1. (2+2)/(-3+4)= 4/1= 4

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y + 2 = 4x + 16

y = 4x + 14 y-intercept:(0,14)

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y + 5 = 5x + 5

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y-intercept (0,0)

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Step-by-step explanation:

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2 years ago
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I think it should be -19


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