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3 years ago

Determine intervals y= -x^3 + 3x^2 -2

Mathematics

1 answer:

motikmotik3 years ago

3 0

Answer:

(2,2) and (0,-2)

Step-by-step explanation:

Use the website desmos for questions like graphing

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Helppp law of sines and law of cosines

Veseljchak [2.6K]

30 30 and 60 is the answer also i went in order

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3 years ago

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Find a vector parametrization for the line with the given description. Perpendicular to the yz-plane, passes through (0, 0, 8)

Brilliant_brown [7]

Answer:

$\left\{\begin{array}{l}x=t\\ \\y=0\\ \\z=8\end{array}\right.$

$\overrightarrow{(t,0,8)}$

Step-by-step explanation:

yz-plane has the equation $x=a,$ where $a$ is a real constant. The normal vector of this plane (vector perpendicular to the plane) is

$\overrightarrow {n}=(1,0,0)$

If the line is perpendicular to this plane, then it is parallel to the normal vector, so the equation of this line is

$\dfrac{x-x_0}{1}=\dfrac{y-y_0}{0}=\dfrac{z-z_0}{0},$

where $(x_0,y_0,z_0)$ are coordinates of the point the line is passing through.

In your case, the line is passing through the point (0,0,8), so the canonical equation of the line is

$\dfrac{x-0}{1}=\dfrac{y-0}{0}=\dfrac{z-8}{0}$

Write a vector parametrization for this line

$\left\{\begin{array}{l}\dfrac{x-0}{1}=t\\ \\\dfrac{y-0}{0}=t\\ \\\dfrac{z-8}{0}=t\end{array}\right.\Rightarrow \left\{\begin{array}{l}x=t\\ \\y=0\\ \\z=8\end{array}\right.$

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3 years ago

Monica purchased adult and youth tickets for the fair. She bought x adult tickets for $28 each and y youth tickets for $15. Writ

WINSTONCH [101]

No its b I read it wrong...sorry

3 0

3 years ago

How many solutions does this have?

olga nikolaevna [1]

Answer:

none ok smrbgeriinjhgfd

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3 years ago

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Please help whoever answers this correctly I'll mark your answer brainliest

djyliett [7]

Answer: The 2nd and 3rd one are correct

Step-by-step explanation:

After reflecting it, the square itself would not change, only the position of the square. Therefore, the same line segments from the beginning which were given would be parallel.

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2 years ago

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