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FrozenT [24]
4 years ago
4

Lin wants to know if flipping a quarter really does have a probability of 1/2 of landing heads up so she flips a quarter 10 time

s it land heads up 3 times and tails up 7 times has she proven that the probability is not 1/2 explain your reasoning
Mathematics
1 answer:
ahrayia [7]4 years ago
4 0

Answer: The answer is NO. Explained.


Step-by-step explanation:  Given that Lin wants to find out that if flipping a quarter really have a probability of 1/2 of head coming up. She flipped the coin 10 times, out of which heads come up 3 times and tail tail come up 7 times.

But this does not prove that the probability is not 1/2. The question here is about theoretical and experimental probability.

Theoretical probability deals with what we expect to happen. That is, whenever we flip a coin, we know either head will come up or tail, so theoretically there is 50% chance of head coming up and 50% chance of tail coming up. So, here probability will be 1/2.

Experimental probability deals with the actual happening. For example, if we flip a coin 10 times like Lin does, the 3 times head come up and 7 times tail come up. So, experimental probability of head coming up is 3/10, i.e., 30% and tail coming up is 7/10, i.e., 70%.

Thus, she didn't prove the the probability is not 1/2 but she explains the difference between theoretical and experimental probability.


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Solve: n^2/2 -2 = 5n/6
garri49 [273]

Answer:

  n = -4/3  or   n = 3

Step-by-step explanation:

Multiply by 6 to eliminate fractions, then put into standard form.

  3n^2 -5n -12 = 0

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8 0
4 years ago
Use the information provided to write the equation of each circle. *photo attached
monitta

Answer:

<em>( x + 13 )^2 +  ( y + 6 )^2 = 1; Option A</em>

Step-by-step explanation:

<em>~ The question we have at hand is: x^2 + y^2 + 26x + 12y + 204 = 0 ~</em>

Let us apply the circle equation ( x - a )^2 + ( y - b )^2 = r^2 ⇒ provided r is the radius, centered at point ( a, b )

1. First rewrite x^2 + y^2 + 26x + 12y + 204 = 0 in the standard form of circle equation: x^2 + y^2 + 26x + 12y + 204 = 0

2. Now move the loose number to the right side: x^2 + 26x + y^2 + 12y = -204

3. Let us now group variables: ( x^2 + 26x ) +  ( y^2 + 12y ) = -204

4. Convert x to square form: ( x^2 + 26x + 169 ) +  ( y^2 + 12y ) = -204 + 169

5. Convert to square form: ( x + 13 )^2 +  ( y^2 + 12y ) = -204 + 169

6. Convert y to square form: ( x + 13 )^2 +  ( y^2 + 12y + 36 ) = -204 + 169 + 36

7. Convert to square form, and simplify: ( x + 13 )^2 +  ( y + 6 )^2 = 1

<em>Answer: ( x + 13 )^2 +  ( y + 6 )^2 = 1</em>

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3 years ago
Please answer please answer
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8 0
3 years ago
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