For a normally distributed data set, approximately 68.27% of the data is within one standard deviation. i.e. approximately 0.6827 x 200 = 137 test scores is between 86 + or - 3 i.e. from 83 to 89. Hence approximately 137/2 = 68 test score is within the 86 to 89 range.
Answer:
Step-by-step expla3
x
−
2
y
<
10
Solve for y
.
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y
>
−
5+
3
x
2
Find the slope and the y-intercept for the boundary line.
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Slope:
3
2
y-intercept:
(
0
,
−
5
)
Graph a dashed line, then shade the area above the boundary line since
y
is greater than
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5
+
3
x
2
.
y
>
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5
+3
x2
The 68 - 95 - 99.7 rule, gives the basis to solve this question.
It says that for a normal distribution 95% of the results are between the mean minus 2 standard deviations and the mean plus 2 standard deviations.
Here:
mean = 64.5 inches,
standard deviaton = 2.5 inches
mean - 2 standard deviations = 64.5 inches - 5 inches = 59.5 inches
mean + 2 standard deviations = 64.5 inches + 5 inches = 69.5 inches
Then, the answer is that 95% of women range approximately between 59.5 inches and 69.5 inches.
It’s 6 because if you divide 12 divided by 2 that’s 6 and to check it multiply 6x2=12
