Y = -6x + 2 . . . . . . . . (1)
-12x - 2y = -4 . . . . . . (2)
Putting (1) into (2), we have
-12x - 2(-6x + 2) = -4
-12x + 12x - 4 = -4
-4 = -4
Therefore, the system has infinite number of solutions.
a)
FH = 102, FG = 5x + 9. HG = 9x - 5 <em>Given</em>
FG + HG = FH <em>Segment addition postulate</em>
5x + 9 + 9x - 5 = 102 <em>Substitution</em>
14x + 4 = 102 <em>Simplify (added like terms)</em>
14x = 98 <em>Subtraction property of equality</em>
x = 7 <em>Division property of equality</em>
b) FG = 5x + 9 = 5(7) + 9 = 35 + 9 = 44
c) HG = 9x - 5 = 9(7) - 5 = 63 - 5 = 58
Answers: a = 7, b = 44, c = 58
Answer:
Step-by-step explanation:
Given the equation j – 16 = 7, If Nolan is using substitution to determine if 23 is a solution to the equation, then Nolan need to make j the subject of the formula from the equation. The following statements must therefore be made by Nolan.
First, Nolan must substitute for the value of j in the equation.
To simplify, Nolan must subtract the value of 7 from both sides to have;
j – 16 - 7= 7 - 7
j – 23 = 0
Then Nolan must add 23 to both sides of the equation to get the value of j as shown;
j – 23 + 23 = 0+23
j = 23
23 is therefore a solution to the equation
Your answer would be A b=a+5