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3 years ago

How can we factorise the expression: 2x^6+17x^3+8?

Mathematics

1 answer:

LekaFEV [45]3 years ago

7 0

Answer:

$(a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1)$

Step-by-step explanation:

$2x^6+17x^3+8 \\ = 2x^6+16x^3 + {x}^{3} +8 \\ = 2{x}^{3} ( {x}^{3} + 8) + 1( {x}^{3} + 8) \\ = ( {x}^{3} + 8)(2 {x}^{ 3} + 1) \\ = ( {x}^{3} + {2}^{3} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + {2}^{2} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1) \\$

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brainly hdd and ram memory both tests both come back with positive old tower pc doesn't always turn on and randomly

mash [69]

The correct option is 4. PSU.

The hardware part that would be checked next is PSU.

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The correct question is-

A customer complains that his old tower PC doesn't always turn on and randomly shut off for hours. The HDD and RAM both tests both come back with positive results.

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6 0

2 years ago

A pharmaticeutical company is making a new medicine capsule shaped like a cylinder with a half sphere at each end. The

DerKrebs [107]

Answer:

339.12 cubic millimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The volume of the figure is equal to the volume of the two hemispheres (one sphere) plus the volume of the cylinder

step 1

Find the volume of the cylinder

The volume is given by

$V=Bh$

where

B is the area of the base of cylinder

h is the height of cylinder

we have

$B=\pi r^{2}$

we have

$h=8\ mm$

$r=6/2=3\ mm$ ----> the radius is half the diameter

$B=(3.14)(3)^{2}$

$B=28.26\ mm^2$

substitute

$V=(28.26)(8)=226.08\ mm^3$

step 2

Find the volume of the sphere

The volume is given by

$V=\frac{4}{3}\pi r^{3}$

we have

$r=6/2=3\ mm$ ----> the radius is half the diameter

substitute

$V=\frac{4}{3}(3.14)(3)^{3}=113.04\ mm^3$

step 3

Adds the volumes

$226.08+113.04=339.12\ mm^3$

6 0

3 years ago

Greetings. As a beginner, I'm struggling a bit to learn calculus. May I know what is the derivative of x to the power 4 step by

elena-14-01-66 [18.8K]

If you're just starting calculus, perhaps you're asking about using the definition of the derivative to differentiate $x^4$ .

We have

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x+h)^4 - x^4}h$

Expand the numerator using the binomial theorem, then simplify and compute the limit.

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x^4+4hx^3 + 6h^2x^2 + 4h^3x + h^4) - x^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} \frac{4hx^3 + 6h^2x^2 + 4h^3x + h^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} (4x^3 + 6hx^2 + 4h^2x + h^3) = \boxed{4x^3}$

In general, the derivative of a power function $f(x) = x^n$ is $\frac{df}{dx} = nx^{n-1}$ . (This is the aptly-named "power rule" for differentiation.)