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asambeis [7]
3 years ago
15

How can we factorise the expression: 2x^6+17x^3+8?​

Mathematics
1 answer:
LekaFEV [45]3 years ago
7 0

Answer:

(a + 2)( {a}^{2}  - 2a +  4 )(2 {x}^{ 3}  + 1)

Step-by-step explanation:

2x^6+17x^3+8 \\  = 2x^6+16x^3 +  {x}^{3} +8 \\  =  2{x}^{3} ( {x}^{3}  + 8) + 1( {x}^{3}  + 8) \\  = ( {x}^{3}  + 8)(2 {x}^{ 3}  + 1) \\  = ( {x}^{3}  +  {2}^{3} )(2 {x}^{ 3}  + 1)  \\  = (a + 2)( {a}^{2}  - 2a +  {2}^{2} )(2 {x}^{ 3}  + 1)   \\  = (a + 2)( {a}^{2}  - 2a +  4 )(2 {x}^{ 3}  + 1)  \\

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