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miv72 [106K]
3 years ago
11

the area of a rectangle is 42.15 square meters. if the length is 21 meters, what is perimeters of the rectangle?

Mathematics
2 answers:
Vsevolod [243]3 years ago
7 0

Answer:

perimeters of the rectangle=p=46.014 metres

Step-by-step explanation:

Given that:

Length (l) = 21 m

Area of rectangle(A) = 42.15 meter-square

Width (w)=?

Required data:

Perimater of Rectangle=p=?

Calculation:

As we know that Area of rectangle=A=l*w

Putting the value we get

42.15 m(square)=(21 m)*w

or w=42.15/21

or w=2.007 m

Now to find perimters of rectangle we know that

p=2(l + w) metres

putting the values

p=2(21+2.007) metres

p=2(23.007) metres

p=46.014 metres

wariber [46]3 years ago
5 0

Answer:perimeter = 46.014 meters

Step-by-step explanation:

The formula for determining the area of a rectangle is expressed as

Area = length × width

The area of a rectangle is given as 42.15 square meters. The length of the rectangle is given as 21 meters. This means that the width of the rectangle would be

Width = area/length = 42.15/21 = 2.007meters.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(length + width)

Perimeter = 2(21 + 2.007) = 23.007 × 2 = 46.014 meters

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