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anzhelika [568]
3 years ago
5

What is the surface area, in square centimeters of a cube with each edge measured 36 centimeters?

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0
7776

because it equals 36*36*6
ale4655 [162]3 years ago
5 0

Answer:

7776 cm^2

Step-by-step explanation:

The surface area of a cube is found using this formula: 6x^2, where x represents the side length of a side of the cube.

Substitute in 36 centimeters for x and solve.

  • 6(36)^2

Evaluate the exponent first.

  • 6(1296)

Multiply 6 and 1296 together to get the final answer.

  • 7776 centimeters^2 is the surface area of the cube.
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The width of a box in the shape of a rectangular prism is 4 inches more than the height h . The length is the difference of 9 in
Doss [256]

Answer:

(a) V = -H^3+ 5H^2 + 36H

(b) Length = 5in; Width = 9in; Height = 5in or Length = 3in; Width = 10in; Height = 6in

Step-by-step explanation:

Let:

W=Width; L = Length; H = Height

Given

W = 4 + H

L = 9 - H

Solving (a): The polynomial for the volume in terms of height

Volume (V) is calculated using:

V = L * W * H

V = (9 - H) * (4 + H) * H

Expand

V = (9 - H) * (4H + H^2)

Open brackets

V = 36H + 9H^2 - 4H^2 - H^3

V = 36H + 5H^2 - H^3

Rewrite as:

V = -H^3+ 5H^2 + 36H

Solving (b): The dimensions when Volume = 180

Substitute 180 for V in: V = -H^3+ 5H^2 + 36H

180 = -H^3+ 5H^2 + 36H

Rewrite as:

H^3 - 5H^2 - 36H + 180 = 0

Factorize:

H^2(H - 5) - 36(H - 5) = 0

(H^2 - 36)(H - 5) = 0

Express H^2 - 36 as difference of two squares

(H - 6)(H + 6)(H - 5) =0

This gives:

H - 6 =0==> H = 6

H + 6 =0==> H = -6

H - 5 =0==> H = 5

Since the height can not be negative, then H = 5 or H = 6

Recall that:

W = 4 + H

L = 9 - H

When H = 5

W = 4 + 5 = 9

L = 9 - 5 = 4

When H = 6

W = 4 + 6 = 10

L = 9 - 6 = 3

Hence, the dimensions of the box are:

Length = 5in; Width = 9in; Height = 5in

or

Length = 3in; Width = 10in; Height = 6in

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Answer:

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Step-by-step explanation:

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Answer:

7.5kilometer

Step-by-step explanation:

for 30mins semin runs 5kilometer

then for 1min: (1min×5kilometer)÷30mins,

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Point M is the midpoint of segment QR. If QM = 16 + x and MR = 2(x + 2), find the length of QR. QR = 12 QR = -12 QR = 28 QR = 56
vfiekz [6]
The midpoint divided a segment into two congruent lengths/segments.

So, QM = MR.

Set up the equation.

16 + x = 2(x+ 2)

16 + x = 2x + 4

12 + x = 2x

12 = x


Now, that you have the value of x, substitute it for the two equations.

QM = 16 + x

QM = 16 + 12

QM = 28


MR = 2(12+ 2)

MR = 2(14)

MR = 28


Find the whole length by of the line by adding the two segments. 28 × 2 = 56.

QR = 56
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Mrs. Higgins's was hoping to make some extra cash, so she invested 12000 in equipment to print yearbooks, each year book cost he
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Answer: im pretty sure it’s the first one

Step-by-step explanation: )

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