You've already told us the speed in ft/s . It's right there in the question. You said that light travels about 982,080,000 ft/s.
We don't know how accurate that number is, but for purposes of THIS question, that's the number we're going with.
In scientific notation, it's written . . . <em>9.8208 x 10⁸ ft/s .</em>
We don't know where you were going with the number of seconds in a year. But to answer the question that you eventually asked, it turned out that we don't even need it.
The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.
At time
, the acceleration vector has direction
such that

which indicates the particle is situated at a point on the lower left half of the circle, while at time
the acceleration has direction
such that

which indicates the particle lies on the upper left half of the circle.
Notice that
. That is, the measure of the major arc between the particle's positions at
and
is 270 degrees, which means that
is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.
Recall that

where
is the radius of the circle and
is the period. We have

and the magnitude of the particle's acceleration toward the center of the circle is

So we find that the path has a radius
of

Answer:
The work done by the weightlifter, W = 700 J
The power of the weightlifter, P = 350 watts
Explanation:
A weightlifter lifts a set of weights a vertical distance, s = 2 m
The force exerted to lift the weight, F = 350 N
The work done by the body is defined as the product of the force applied by the body to the displacement it caused.
W = F x s
= 350 N x 2 m
= 700 J
The work done by the weightlifter, W = 700 J
The time taken by the weightlifter to lift the weight, t = 2 s
The power is defined as the rate of body to do work. It is given by the equation,
P = W / t
= 700 J / 2 s
= 350 watts
Hence, the power of the weightlifter, P = 350 watts
R=u^2 sin2x / g
7.8=u^2 sin2*30 /10
u=9.5m/s