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Katen [24]
3 years ago
9

A yo-yo is made of two solid cylindrical disks, each of mass 0.055 kg and diameter 0.070 m , joined by a (concentric) thin solid

cylindrical hub of mass 0.0055 kg and diameter 0.011 m . Part A Use conservation of energy to calculate the linear speed of the yo-yo when it reaches the end of its 1.1 m long string, if it is released from rest. Express your answer using three significant figures and include the appropriate units.
Physics
2 answers:
DedPeter [7]3 years ago
6 0

Answer: IM 95%sure that the answer is B jus took the test got the answer right

Explanation:

melisa1 [442]3 years ago
3 0

Answer:

sorry I forgot I wish I could help

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How do scientists construct models of atoms and molecules?
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A racing car is travelling at 70 m/s and accelerates at -14 m/s2. What would the car’s speed be after 3 s?
Leno4ka [110]
<h3><u>Question</u><u>:</u></h3>

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?

<h3><u>Statement:</u></h3>

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.

<h3><u>Solution</u><u>:</u></h3>
  • Initial velocity (u) = 70 m/s
  • Acceleration (a) = -14 m/s^2
  • Time (t) = 3 s
  • Let the velocity of the car after 3 s be v m/s
  • By using the formula,

v = u + at, we have

v = 70 + ( - 14)(3) \\  =  > v = 70 - 42 \\  =  > v = 28

  • So, the velocity of the car after 3 s is 28 m/s.
<h3><u>Answer:</u></h3>

The car's speed after 3 s is 28 m/s.

Hope it helps

3 0
3 years ago
Pls help me!!!!! Brainliest
Studentka2010 [4]

Answer:

B, C

Explanation:

7 0
3 years ago
Read 2 more answers
A locomotive is pulling 8 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (wi
nikitadnepr [17]

Answer:106560 N

Explanation:

Given

Let Tension between  2 and 3 car be T_{23} and between 3 &4 is T_{34}

T_{23}-T_{34}=ma

mass of freight car =37,000 kg

acceleration of car=0.48 m/s^2

T_{34} is accelerating all freights behind 3

therefore

T_{34}=5\times ma

T_{34}=5\times 37000\times 0.48=88,800 N

Thus

T_{23}=T_{34}+ma

T_{23}=88,800+37000\times 0.48=88,800+17,760=106560 N

4 0
4 years ago
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