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Nezavi [6.7K]
3 years ago
6

g Adjacent rows in the first part of the experiment are found to have potentials of 3.66 V and 4.22 V. If the distance between r

ows is found to be 0.4 cm, what is the magnitude of the electric field at the location between the rows
Physics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

E=140V/m

Explanation:

If the electric field is uniform, the electric field between two points at potentials V_1 and V_2 which are separated by a distance <em>d</em> will be given by the formula:

E=\frac{\Delta V}{d}

So in our case, we have E=\frac{4.22V-3.66V}{0.004m}=140V/m

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