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muminat
3 years ago
6

A research report says that t(63) = 1.99; p = .03. From that information, can you reject the null hypothesis with 95% confidence

? No. Yes. It depends on the sample size. It depends on the size of the Type I error.
Mathematics
2 answers:
nika2105 [10]3 years ago
5 0

Answer:

Yes, we can reject the null hypothesis with 95% confidence.

Step-by-step explanation:

We are given that t(63) = 1.99; p = .03 and confidence level = 0.95

Confidence Level = 95% = 0.95

Significance level (\alpha) = 1 - 0.95 = 0.05 or 5%

P- value = 0.03 or 3%

As we know that;

           If p-value < significance level  ⇒ Reject null hypothesis

            If p-value > significance level  ⇒ Accept null hypothesis

Since, P-value is less than significance level as 3% < 5%, so we can reject null hypothesis with 95% confidence.

Leona [35]3 years ago
4 0

Answer:

Yes, I can reject the null hypothesis with 95% confidence.

Step-by-step explanation:

Critical value t(63) = 1.99

p-value = 0.03

Confidence level (C) = 95% = 0.95

Significance level = 1 - C = 1 - 0.95 = 0.05

Conclusion:

Reject the null hypothesis because the p-value 0.03 is less than the significance level 0.05.

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Answer:

Three fractions that are equivalent to \frac{3}{11} are: \frac{6}{22}, \frac{24}{88} and \frac{144}{528}.

Step-by-step explanation:

Equivalent fractions are set of fractions in which when simplified, they have the same answer.

Given: \frac{3}{11}

i. multiply the numerator and denominator of \frac{3}{11} by 2,

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i. multiply both the numerator and denominator of \frac{6}{22} by 4,

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ii. multiply the numerator and denominator of \frac{24}{88} by 6,

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