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Inessa [10]
3 years ago
8

Number between 61 and 107 that is multiple of 2,6 and 8

Mathematics
2 answers:
Fed [463]3 years ago
4 0
The answer to that is 72 and 96. :)
mariarad [96]3 years ago
3 0
Not saying my answer is 100% correct but I quickly tried to solve this and got 72.
(2x36, 6x12, 8x9)
You might be interested in
ASAP PLZ
Nimfa-mama [501]

As per the problem

The chemicals in my swimming pool use a ratio of 5 tablets of chlorine for every 14 days.

we have been asked to find

Which ratio shows the number of chlorine tablets needed for 42 days?

Since for each 14 days the number of tablets required is 5

So if you multiply the number of days by some number then, we will have to multiply the number of tablets required by the same number.

So When number of days=14*3=42\\

Then the number of tablets required for 42 days is =5*3=15\\

6 0
3 years ago
Read 2 more answers
Select the correct answer.
MrRissso [65]

Answer:

C. 309 cm2

Step-by-step explanation:

A=2(1+sqr2)a^2

A=2(1+sqr2)8^2

≈309.01934

3 0
2 years ago
Please help meeeee
miskamm [114]

Answer:

the graph has opposite x intercepts of b and -b. the graph has y intercepts at –b². the graph of the function symmetrical about the y-axis.

Step-by-step explanation:

3 0
3 years ago
The velocity,v of a missile is related to time t, By the equation v=5t^2+3t+1.calculate the time at which the velocity is minimu
Cloud [144]

Answer:

  • time: t = -0.3
  • minimum: v = 0.55

Step-by-step explanation:

For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...

  t = -(3)/(2(5))

  t = -0.3 . . . . . time of minimum velocity

__

The value of velocity at that time is ...

  v = 5(-0.3)^2 +3(-0.3) +1 = 5(.09) -.9 +1

  v = 0.55 . . . . . value of minimum velocity

3 0
3 years ago
Suppose that documentation lists the average sales price of a single-family home in the metropolitan Dallas/Ft. Worth/Irving, Te
Julli [10]

Answer:

"0.0373" seems to be the appropriate solution.

Step-by-step explanation:

The given values are:

n₁ = 43

n₂ = 35

\bar{x_1}=217800

\bar{x_2}=204700

\sigma_1=30300

\sigma_2=33800

Now,

The test statistic will be:

⇒  Z=\frac{\bar{x_1}-\bar{x_2}}\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }

On substituting the given values in the above formula, we get

⇒      =\frac{217800-204400}{\sqrt{\frac{(30300)^2}{43} +\frac{(33800)^2}{35} } }

⇒      =\frac{217800-204400}{\sqrt{\frac{918090000}{43} +\frac{1142440000}{35} } }

⇒      =\frac{13400}{7347.93}

⇒      =1.7828

then,

P-value will be:

=  P(Z>1.7828)

=  0.0373

8 0
2 years ago
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