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Galina-37 [17]
3 years ago
9

Select two polynomials that have a sum of 16n^3+13n^2+7n-10 A. 8n^3 - 5n +11n^2 - 5 B. 7n^2 + 8n - n^3 + 2 C. 15n^2 - 10n + 3n^3

- 4 D. 2n^2 + 12n - 5 + 8n^3
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

We have the polynomial

16n^3+13n^2+7n-10   ( 1 )

To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

8n_{3}-5n+11n^{2}-5\\7n^2 + 8n - n^3 + 2\\15n^2 - 10n + 3n^3 - 4\\2n^2 + 12n - 5 + 8n^3

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have

8n^3 +11n^2 - 5n  - 5\\ 8n^3+2n^2 + 12n - 5\\

and if we sum we obtain

16n^3+13n^2+7n-10

that is what we was looking for

I hope this is useful for you

regards

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The amount that the would be paid after 40% discount is $27

<h3>Word Problem</h3>

Given Data

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Let us find 40% discount of $45

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2 years ago
Literally noone answers my questions please help
prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

Total distance = 695+795 = 1490

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Answer:

4x - y = -5

Step-by-step explanation:

The equation of a new line which is parallel to old line 4x - y = 14 looks exactly the same as that of the old line EXCEPT that we replace the constant, 14, with C and find C for the line that passes through (-2, -3).

4x - y = 14     becomes     4x - y =  C

Now substitutte -2 for x, -3 for y and calculate C:

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Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

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Applying Pythagoras theorem:

(Hypotenuse)^2  = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm

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