Find the coordinates of the center of the following circle. (x + 3)2 + (y - 6)2 = 24

2 answers:

4 0

<span>the equation of a circle with the center at (h,k0 is given by the equation where the r is obviously the radius of the circle then do (x+3) ^2
(y-6)^2= 24 which shows that the center is = to (-3,6)
</span>

Levart [38]3 years ago

3 0

Answer: (-3,6)

Step-by-step explanation:

We know that the standard equation a circle is given by ":-

$(x-h)^2+(y-k)^2=r^2$ , where r is the center of the circle and (h,k) is the center of the circle.

The given equation of the circle : $(x +3)^2+ (y - 6)^2 = 24$

which is equivalent to $(x -(-3))^2 + (y - 6)^2 = 24$

It implies the coordinates of the center of the given circle =(-3,6)

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