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pochemuha
3 years ago
15

Find the coordinates of the center of the following circle. (x + 3)2 + (y - 6)2 = 24

Mathematics
2 answers:
irga5000 [103]3 years ago
4 0
<span>the equation of a circle with the center at (h,k0 is given by the equation where the r is obviously the radius of the circle then do (x+3) ^2
(y-6)^2= 24 which shows that the center is = to (-3,6)
</span>
Levart [38]3 years ago
3 0

Answer: (-3,6)

Step-by-step explanation:

We know that the standard equation a circle is given by ":-

(x-h)^2+(y-k)^2=r^2, where r is the center of the circle and (h,k) is the center of the circle.

The given equation of the circle : (x +3)^2+ (y - 6)^2 = 24

which is equivalent to (x -(-3))^2 + (y - 6)^2 = 24

It implies the coordinates of the center of the given circle =(-3,6)

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<u>Answer:</u>

The correct answer option is: infinitely many solutions.

<u>Step-by-step explanation:</u>

We are given the following system of equations:

3 x - 2 y = 6 --- (1)

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Dividing equation (2) by 2 to get:

3 x - 2 y = 6 --- (3)

As the equation (3) is same as the equation (1), therefore the system will have infinitely many solutions.

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given that BD is both the median and altitude of triangle ABC, congruence postulate SAS is used to prove that triangle ABC is wh
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Isosceles

Step-by-step explanation:

Consider triangle ABC, BD is the median and the altitude drawn to the side AC. This segment (BD) divide the triangle ABC into two triangles: ABD and CBD.

In these triangles:

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cupoosta [38]

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