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Tomtit [17]
3 years ago
10

Help please its timed​

Mathematics
1 answer:
igomit [66]3 years ago
7 0

Answer:

15

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out expression

2² + 6(3) - 7

Step 2: Evaluate exponents

4 + 6(3) - 7

Step 3: Evaluate parenthesis (multiply)

4 + 18 - 7

Step 4: Add

22 - 7

Step 5: Subtract

15

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A car purchased for $17,500. After each year the resale value decreases by 20%. What will the resale value be after 4 years? Rou
Tema [17]
The value at the end of the year is 100% - 20% = 0.80 of the value at the beginning of the year. After 4 years of multiplying by this factor, the value is
  $17,500·0.80⁴ = $7,168
3 0
3 years ago
WILL GIVE BRAINLIEST PLEASE HELP
Debora [2.8K]

Answer:

the 3 one is the correct answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A complete graph of the polynomial function f is provided. Use your knowledge of the domain, range, behavior at each x intercept
Papessa [141]

The graph represents a polynomial graph, and the equation of the polynomial graph is f(x) = -(x + 5)³(x - 2)²

<h3>How to determine the equation?</h3>

From the graph, we have the following observations:

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  • The graph changes the factor of its direction at x = -5

This means that the graph has a multiplicity of 2 at x = 2 and a multiplicity of 3 at x = -5

So, we have:

f(x) = a(x + 5)³(x - 2)²

The curve is inverted,

This means that a < 0

Assume a = -1.

Then, we have:

f(x) = -(x + 5)³(x - 2)²

Hence, the equation of the polynomial graph is f(x) = -(x + 5)³(x - 2)²

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3 0
1 year ago
Help on this dccr Pleaseeeeeeee
forsale [732]
1.C
2.C
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5.Depends on your way of learning what is "compatible"
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7 0
2 years ago
One day, eleven babies are born at a hospital. Assuming each baby has an equal chance of being a boy or girl, what is the probab
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You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1.  This will give probability that any other number up to 9 of the babies are girls.

Use binomial theorem.
P(x=k) = (nCk) p^k (1-p)^{n-k}

n = 11
k = 10,11
p = 1/2

P(x=10) = 11 (\frac{1}{2})^{11} = \frac{11}{2048} \\  \\ P(x=11) = 1(\frac{1}{2})^{11} = \frac{1}{2048} \\  \\ P(x \leq 9) = 1 - \frac{11}{2048} - \frac{1}{2048} \\  \\ P(x \leq 9)=\frac{2036}{2048} = \frac{509}{512}
4 0
3 years ago
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