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3 years ago

Help please its timed

Mathematics

1 answer:

igomit [66]3 years ago

7 0

Answer:

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out expression

2² + 6(3) - 7

Step 2: Evaluate exponents

4 + 6(3) - 7

Step 3: Evaluate parenthesis (multiply)

4 + 18 - 7

Step 4: Add

22 - 7

Step 5: Subtract

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Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

7 0

4 years ago

Help please its timed​

Help please its timed