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Alina [70]
2 years ago
11

Which of the following expressions is NOT equivalent to (x − 6)(x − 3)?

Mathematics
1 answer:
kodGreya [7K]2 years ago
4 0

Answer:

B. x(x) + (−6)(−3)

NOT equivalent  to (x − 6)(x − 3)

Step-by-step explanation:

(x − 6)(x − 3)

= x^2 - 3x - 6x + 18

= x^2 - 9x + 18

A. (6 − x)(3 − x)

= 18 - 6x - 3x + x^2

= 18 - 9x + x^2

= x^2  - 9x + 18  ---->equivalent  to (x − 6)(x − 3)

B. x(x) + (−6)(−3)  = x^2 + 18   ----> NOT equivalent  to (x − 6)(x − 3)

C. x2 − 3x − 6x + 18   = x^2 - 9x + 18  --> equivalent  to (x − 6)(x − 3)

D. x(x − 6) − 3(x − 6)

= x^2 - 6x - 3x + 18

= x^2  - 9x + 18  ---->equivalent  to (x − 6)(x − 3)

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
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Answer:

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Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

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Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

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Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

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Answer:

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Step-by-step explanation:

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