Answer:
Step-by-step explanation:
Which of the following expressions is NOT equivalent to (x − 6)(x − 3)?
1 answer:
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Using the determinant method, the cross product is
so the answer is B.
Or you can apply the properties of the cross product. By distributivity, we have
(3i + 8j - 6k) x (-4i - 2j - 3k)
= -12(i x i) - 32(j x i) + 24(k x i) - 6(i x j) - 16(j x j) + 12(k x j) - 9(i x k) - 24(j x k) + 18(k x k)
Now recall that
- (i x i) = (j x j) = (k x k) = 0 (the zero vector)
- (i x j) = k
- (j x k) = i
- (k x i) = j
- (a x b) = -(b x a) for any two vectors a and b
Putting these rules together, we get
(3i + 8j - 6k) x (-4i - 2j - 3k)
= -32(-k) + 24j - 6k + 12(-i) - 9(-j) - 24i
= (-12 - 24)i + (24 + 9)j + (32 - 6)k
= -36i + 33j + 26k
Tess and Jack are both correct with their claims
<h3>How to determine who is correct?</h3>The attached image completes the question
From the complete question, we have the following highlights
- The shape has equal side lengths
- The angles at the vertices of the shape are right angles
The above properties represent a square
A rhombus can also have the above properties when the vertices are at 90 degrees
Hence, Tess and Jack are both correct with their claims
Read more about squares and rhombus at:
#SPJ1
