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steposvetlana [31]
2 years ago
14

Please answer 12. How ever gets it right will get brainlyest

Mathematics
2 answers:
muminat2 years ago
4 0

Answer:

-6.5

Step-by-step explanation:

-18-2-6+14=26

-26/4=-6.5

Travka [436]2 years ago
3 0

Answer: -3 yards

Step-by-step explanation:

-2+14+-18+-6 = -12/4 = -3

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Find the area of a circle having a radius of 9 cm
iVinArrow [24]

Answer:

81 pi cm^2

or approximately 254.34 cm^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi (9)^2

A = 81 pi

Using 3.14 as an approximation for pi

A = 81 (3.14)

A =254.34 cm^2

7 0
3 years ago
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I have a question about this fraction question​
Misha Larkins [42]

Answer:

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8 0
2 years ago
Evaluate the function.<br> f(x) = 2x2<br> Find f(-3)<br><br> Can anybody answer this?
o-na [289]

Answer:

18

Step-by-step explanation:

f(x) = 2x^2

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6 0
3 years ago
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kondor19780726 [428]

I haven't done this in a while, but I'm pretty sure the answer is D, (-3, -1.)

If you were to substitute x for -3 and y for -1 in the first inequalities and simplify, it would look like this:

-1 > -3-2

-1 > - 5

And that inequality is true, because -1 is bigger than -5. Let's also substitute in the other inequality, which would be:

-1 > 2(-3) + 2

-1 > -6 + 2

-1 > -4

And -1 is bigger than -4. So, I think the answer would be D because substituting for those values of x and y would stil. make the inequalities true.

5 0
3 years ago
Suppose that you are a city planner who obtains and sample of 20 randomly selected members of a mid-sized town in order to deter
Dmitry_Shevchenko [17]

Answer:

The critical value for the 95% confidence interval is z = 1.96.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96.

The critical value for the 95% confidence interval is z = 1.96.

5 0
3 years ago
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