(15p⁺⁴.q⁻⁶) /(-20p⁻¹².q⁻³).
Remember that a⁻ⁿ = 1/aⁿ and 1/a⁻ⁿ = aⁿ
(-15/4).(p⁻⁴.q⁻⁶)(p⁺¹².q⁺³).
(-15/20).(p⁻⁴.p¹².q⁻⁶.q³)
Remember aⁿ.aˣ = aⁿ⁺ˣ
(-15/20).(p⁸.q⁻³)
-3/5(p⁸.q⁻³)
Answer:
simple we divide 3 by its denominator 8 to get : 0.375
Step-by-step explanation:
Answer: b , d , e ( hope this helps ) :D
-2 ≥ u - 11 > -3
Add 11 to both sides:
9 ≥ u > 8
Answer: 9 ≥ u > 8
Answer:
sum was 300000
Step-by-step explanation:
let sum of money is placed is x rs
Term T = 3 years, rate R = 10%
Then simple interest for for 3 years is

Sum of x will become x+0.3x = 1.3x after 3 years. now this 1.3x is kept for compound interest for two years. ie
![A =P[1+R]^t\\471900=1.3x[1+\frac{10}{100} ]^2\\x=\frac{471900}{1.573} \\x=300000](https://tex.z-dn.net/?f=A%20%3DP%5B1%2BR%5D%5Et%5C%5C471900%3D1.3x%5B1%2B%5Cfrac%7B10%7D%7B100%7D%20%5D%5E2%5C%5Cx%3D%5Cfrac%7B471900%7D%7B1.573%7D%20%5C%5Cx%3D300000)
Sum was 300000