Fine but I ain't showing my work completely.
The sum of all ext. angles of a polygon = 360.
So, you make this formula and solve for x.
360 = 49 + (3x+30) + (14x+6) + (6x-3) + (4x+8)
360 = 49 + 27x + 30 + 6 -3 + 8
360 = 90 + 27x
270 = 27x
/27 /27
10 = x
Now substitute for angle A, which is (6x-3)
6x-3
6(10)-3
60-3
57
Therefore, angle A is 57 degrees.
4.7 = 4 + 0.7
7/10
4 7/10
Answer: D)
I believe the answer is
sin(6x)
Assume N students
Student 1 can get (n-1) papers
Student 2 can get (n-1) papers
Student 3 can get (n-1) papers
etc
Student N can get (n-1) papers
So for N students you can have N(n-1)
